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DanielleElmas [232]
3 years ago
10

What do elements in the same group have? the same atomic mass the same number of electron shells similar properties similar atom

ic numbers
Chemistry
2 answers:
djyliett [7]3 years ago
5 0
They all have the same number of electrons in their outer shell.
Brrunno [24]3 years ago
3 0

Answer:

They all have the same number of electrons in their outer shell.

Explanation:

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What’s the Difference between attractive forces and ionic/covalent/metallic bonds
Deffense [45]

Answer:

Explanation:The main difference between ionic covalent and metallic bonds is their formation; ionic bonds form when one atom provides electrons to another atom whereas covalent bonds form when two atom shares their valence electrons and metallic bonds form when a variable number of atoms share a variable number of electrons in a metal lattice.

7 0
2 years ago
What happens when gasoline is used to power a vehicle?
olga55 [171]
Well cars need gas to run on if the car does not have gas it wont run and you cant get to places you need to go only if you have gas.

5 0
3 years ago
Number of H in 3(NH4)2Cro4
zlopas [31]

The number of H atoms in 3(NH₄)₂CrO₄ = 24

<h3>Further explanation  </h3>

The empirical formula is the smallest comparison of atoms of compound forming elements.  

A molecular formula is a formula that shows the number of atomic elements that make up a compound.  

(empirical formula) n = molecular formula  

Subscripts in the chemical formula indicate the number of atoms

The compound of 3(NH₄)₂CrO₄ ( 3 molecules of (NH₄)₂CrO₄ ) :

Number of H :

\tt 4\times 2(subscript)\times 3(coefficient,number~of~molecules)=24~atoms

7 0
3 years ago
Consider the combustion reaction for octane (C8H18), which is a primary component of gasoline.
lesya692 [45]

Answer:

n_{CO_2}=1.93 gCO_2

Explanation:

Hello,

In this case, considering the given chemical reaction, we can use the molar mass of octane (114.23 g/mol) and the 2:16 molar ratio with carbon dioxide to compute the emitted moles of CO2 to the atmosphere via the following stoichiometric procedure:

n_{CO2}=27.6gC_8H_{18}*\frac{1molC_8H_{18}}{114.23gC_8H_{18}}  *\frac{16molCO_2}{2molC_8H_{18}} \\\\n_{CO_2}=1.93 gCO_2

Which also corresponds to the following mass:

m_{CO_2}=1.93molCO_2*\frac{44gCO_2}{1molCO_2} \\\\m_{CO_2}=85.0gCO_2

Best regards.

6 0
3 years ago
State 3 properties of acid​
zaharov [31]

Explanation:

taste sour (vinegar)

smell frequently burns nose

texture sticky

5 0
3 years ago
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