2 Na + 2 H2O --> 2 NaOH + H2
Answer:
5.16 gm of SO3 formed with 2 g of S
Explanation:
Mole weight of S in the equation = 2 * 32 = 62 gm
Mole weight os O2 in the equation 6 * 16 =96 gm
From the BALANCED equation the grams of S to O2 is
62 to 96 so 2 g of S will need approx 3 gm of O2
this shows that S is the limiting reactant------>
there will be O left over (approx 1 gram)
SO3 mole weight produced from the equation is 2 (32)(3*16) = 160 gm
62 gm of S produces 160 gm of SO3
62/160 = 2 / x x = 5.16 gm of SO3 are formed
The molecular weight is 18, and 16 of that is oxygen.
So, water is 16/18 * 100 = 88.9% oxygen by weight.
None of the other compounds have as high an oxygen content (by weight) as water.
This is a trick question, and the University Chemistry grad fell for it.
If you have the same weight of each compound (let's say, 10 grams, for example), then H2O has the most oxygen weight (8.89 g).
Longitudinal. (just remember that Transverse waves are perpendicular. T is like an inverted perpendicular sign)
Ionic bond forms between metal and non-metal.
Na is a metal, and F is a nonmetal.
Na and F form ionic bond.
