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2 years ago

How we write alkane to Carboxylic acids when n=1,n=3?

1 answer:

7 0

The IUPAC name of a carboxylic acid is derived from that of the longest carbon chain that contains the carboxyl group by dropping the final -e from the name of the parent alkane and adding the suffix -oic followed by the word “acid.” The chain is numbered beginning with the carbon of the carboxyl group.

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Identify each substance as an acid or a base and write a chemical equation showing how it is an acid or a base according to the

faust18 [17]

Answer:

(a) Acid

(b) Base

(d) Base

Explanation:

According to the Arrhenius acid-base theory:

An acid is a substance that releases H⁺ in aqueous solution.

A base is a substance that releases OH⁻ in aqueous solution.

(a) H₂SO₄ is an acid according to the following equation:

H₂SO₄(aq) ⇒ 2 H⁺(aq) + SO₄²⁻(aq)

(b) Sr(OH)₂ is a base according to the following equation:

Sr(OH)₂(aq) ⇄ Sr²⁺(aq) + 2 OH⁻(aq)

(c) HBr is an acid according to the following equation:

HBr(aq) ⇒ H⁺(aq) + Br⁻(aq)

(d) NaOH is a base according to the following equation:

NaOH(aq) ⇒ Na⁺(aq) + OH⁻(aq)

6 0

3 years ago

(a) 4.64 x 1024 atoms Bi into grams

nexus9112 [7]

Answer:

1610.7 g is the weigh for 4.64×10²⁴ atoms of Bi

Explanation:

Let's do the required conversions:

1 mol of atoms has 6.02×10²³ atoms

Bi → 1 mol of bismuth weighs 208.98 grams

Let's do the rules of three:

6.02×10²³ atoms are the amount of 1 mol of Bi

4.64×10²⁴ atoms are contained in (4.64×10²⁴ . 1) /6.02×10²³ = 7.71 moles

1 mol of Bi weighs 208.98 g

7.71 moles of Bi must weigh (7.71 . 208.98 ) /1 = 1610.7 g

5 0

3 years ago

How many liters of nitrogen gas is produced if 50.0L of water is produced at STP?

Alona [7]

Answer:

25.0 liter of nitrogen gas

Explanation:

1. Chemical equation

Ammonium nitrite is a solid compound that decomposes into nitrogen gas and water vapor as per this chemical equation:

$NH_4NO_2(s)\rightarrow N_2(g)+2H_2O(g)$

2. Mole ratio

$1molN_2(g)/2molH_2O(g)$

3. Volume ratio

Since, both species are gases and are at same temperature and pressure, the volume ratio is equal to the mol ratio.

Thus, the volume ratio is:

$1literN_2(g)/2literH_2O(g)$

4. Use the volume ratio with the known amount of water produced

$50.0literH_2O(g)\times 1literN_2(g)/2literH_2O(g)=25.0literN_2(g)$

8 0

2 years ago

Which of the following gas samples would contain the same amount of gas as 200 mL of helium, He(g), at 25° C and 1 atm?

monitta

Answer:

$200\; \rm mL$ of neon $\rm Ne\, (g)$ at $25^{\circ} \rm C$ and $1\; \rm atm$ (the second choice) would contain an equal number of gas particles as $200\; \rm mL\!$ of $\rm He \, (g)$ at $25^{\circ} \rm C\!$ and $1\; \rm atm\!$ (assuming that all four gas samples behave like ideal gases.)

Explanation:

By Avogadro's Law, if the temperature and pressure of two ideal gases is the same, the number of gas particles in each gas would be proportional to the volume of that gas.

All four gas samples in this question share the same temperature and pressure. Hence, if all these gases are ideal gases, the number of gas particles in each sample would be proportional to the volume of that sample. Two of these samples would contain the same number of gas particles if and only if the volume of the two samples is equal to one another.

The second choice, $200\; \rm mL$ of neon $\rm Ne\, (g)$ at $25^{\circ} \rm C$ and $1\; \rm atm$ , is the only choice where the volume of the sample is also $200\; \rm mL \!$ . Hence, that choice would be the only one with as many gas particles as $200\; \rm mL\!$ of $\rm He \, (g)$ at $25^{\circ} \rm C\!$ and $1\; \rm atm\!$ .

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3 years ago

The liquid-phase reaction follows an elementary rate law and is carried out isothermally in a flow system. The concentrations of

Vera_Pavlovna [14]

e kajajdjae no squo viboes we eso doadks Answer:ipao han meExplanation:no

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3 years ago

How we write alkane to Carboxylic acids when n=1,n=3?​

How we write alkane to Carboxylic acids when n=1,n=3?