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2 years ago

How we write alkane to Carboxylic acids when n=1,n=3?

1 answer:

7 0

The IUPAC name of a carboxylic acid is derived from that of the longest carbon chain that contains the carboxyl group by dropping the final -e from the name of the parent alkane and adding the suffix -oic followed by the word “acid.” The chain is numbered beginning with the carbon of the carboxyl group.

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What is 14.235 rounded to the nearest tenth

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It would end up being 14.2

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The corner where a perfume is initally sprayed has:

BartSMP [9]

Answer D; if you spray perfume into a corner, it will eventually diffuse, but initially it has a higher concentration than all other corners of that room.

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3 years ago

Given the molar absorptivity for a species X of 1600 M-1cm-1 at a wavelength of 270 nm, and 400 M-1cm-1 at a wavelength of 540 n

Andre45 [30]

Answer:

Explanation:

From the given information:

At wavelength = 270 nm

$\varepsilon x_1 = 1600 \ m^{-1} \ cm^{-1} \\ \\ \varepsilon y_1 = 200 \ m^{-1} \ cm^{-1}$

At 270 nm

Suppose x is said to be the solution for the concentration of x and y to be the solution for the concentration of y;

Then:

$\varepsilon x_1 \ l + \varepsilon y_1 \ l= 0.5 \\ \\ A = A_1 + A_2$

$1600 xl + 200 yl= 0.5$

Divide both sides by 200

$8xl + yl = \dfrac{0.5}{200}$

$8x + y = \dfrac{0.5}{200}l$

Use l = 1cm (i.e the standard length)

Then;

$8x + y = \dfrac{0.5}{200} ---- (1)$

$\varepsilon x_2 x \ l + \varepsilon y_2 y \ l= 0.5 \\ \\ 40 xl + 800 yl = 0.5$

$x + 20 y = \dfrac{0.5}{400 \ l}$

since l = 1

$x + 20 y = \dfrac{0.5}{400 \ } --- (2)$

Equating both (1) and (2) together, we have:

$8x + y - 8x - 160 y = \dfrac{0.5}{200} - \dfrac{0.5 \times 8}{400} \\ \\ \implies - 159 y = \dfrac{0.5}{200} ( 1 - \dfrac{8}{2}) \\ \\ -159 y = \dfrac{-0.5 \times 3}{200} \\ \\ 159 \ y = 0.0075 \\ \\ y = \dfrac{0.0075}{159} \\ \\ y = 0.00004716 \\ \\ y = 4.7 \times 10^{-5 } \ M$

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3 years ago

A gas occupies 100.0 mL at a pressure of 780 mm ahh. What is the volume of the gas when it’s pressure is increased to 880 mm Hg

vlabodo [156]

Hello!

The volume of the gas when its pressure is increased to 880 mm Hg is 88,64 mL

This question can be easily answered using the Boyle's Law, which states that as pressure increases, the volume is lower. It can be expressed in a mathematical way as follows:

$P_1*V_1=P_2*V_2$

So, from this equation we can clear V₂ to find the volume at 880 mm Hg:

$V_2= \frac{P_1*V_1}{P_2}= \frac{780 mmHg*100 mL}{880 mmHg}=88,64 mL$

Have a nice day!

4 0

3 years ago

How we write alkane to Carboxylic acids when n=1,n=3?​

How we write alkane to Carboxylic acids when n=1,n=3?