Answer:
A) all values of x, and all values of y
B) (3a + 4b) (9a² − 12ab + 16b²)
Step-by-step explanation:
(x² + y²)² = (x² − y²)² + (2xy)²
x⁴ + 2x²y² + y⁴ = x⁴ − 2x²y² + y⁴ + 4x²y²
x⁴ + 2x²y² + y⁴ = x⁴ + 2x²y² + y⁴
27a³ + 64b³
(3a)³ + (4b)³
(3a + 4b) (9a² − 12ab + 16b²)
Answer:
x + y = 3 x - y = 1 --------- 2x + 0y = 4 2x = 4 (2x)/2 = 4/2 x = 2
Step-by-step explanation:
hope i am right
The first part of the answer is 20x+9
Second part is 4a-6b
Post the situations maybe?
The <em>correct answers</em> are:
A) Both can be solved by graphing;
C) Both can be solved by substitution; and
D) Both have solutions at the points of intersection.
Explanation:
Just as a system of linear equations can be solved by graphing, a system of quadratic equations can as well. We graph both equations. We then look for the intersection points of the graphs; these intersection points will be the solutions to the system.
We can also solve the system by substitution. If we can get one variable isolated, we can substitute this into the other equation to solve.
