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NemiM [27]
3 years ago
8

Is the amount of water on earth always changing or is it a constant amount?​

Chemistry
2 answers:
Jlenok [28]3 years ago
8 0
It fairly consistent
Zolol [24]3 years ago
4 0

Answer:

The amount of water on the Earth is constant, or nearly so. Actually, the amount is increasing ever so slightly due to volcanic eruptions expelling water vapor into the atmosphere, but, for all practical purposes, the amount of water (as a gas, liquid and as snow and ice) can be considered to be constant.

Explanation:

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A mysterious compoud with the chemical formula MX (Ksp 1.27x10-36) is present in two different solutions. What is its molar solu
qwelly [4]

<u>Answer:</u> The molar solubility of MX is 2.54\times 10^{-36}M

<u>Explanation:</u>

We are given:

K_{sp}(MX)=1.27\times 10^{-36}

The chemical equation for the ionization of MX follows:

MX\rightleftharpoons M^+(aq.)+X^-(aq.)

                  S         S

The expression of K_{sp} for above equation is:

K_{sp}=S\times S      ......(1)

The chemical equation for the ionization of M_2SO_4 follows:

M_2SO_4\rightleftharpoons 2M^+(aq.)+SO_4^{2-}(aq.)

 0.25M           0.5M      0.25M

Total concentration of cation from both the equation is:

[M^+]=0.5+S

As, K_{sp}(MX), so S is also very very less than 1 and can be easily neglected.

So, [M^+]=0.5M

Putting values in equation 1, we get:

1.27\times 10^{-36}=0.5\times S\\\\S=2.54\times 10^{-36}M

Hence, the molar solubility of MX is 2.54\times 10^{-36}M

4 0
3 years ago
If 5.0 g of each reactant were used for the the following process, the limiting reactant would be: 2KMnO4 + 5Hg2Cl2 + 16HCl -&gt
IceJOKER [234]

Answer:

The limiting reactant is Hg2Cl2.

Explanation:

Step 1: Data given

Mass of each reactant = 5.0 grams

KMnO4 MM=158 g/mol

Hg2Cl2 MM=472.1 g/mol

HCl MM=36.5 g/mol

HgCl2 MM=271.5 g/mol

MnCl2 MM=125.8 g/mol

KCl MM=74.6 g/mol

H2O MM=18 g/mol)

Step 2: The balanced equation

2KMnO4 + 5Hg2Cl2 + 16HCl -> 10HgCl2 + 2MnCl2 + 2KCl + 8H2O

Step 3: Calculate moles

KMnO4 = 5.00 grams / 158 g/mol = 0.0316 mol

Hg2CL2 = 5.00 grams / 472.1 g/mol = 0.0106 mol

HCl = 5.00 grams / 36.5 g/mol = 0.137 mol

Step 3: Calculate limiting reactant

For 2 moles of KMno4 we need 5 moles of Hg2Cl2 and 16 moles of HCl

Hg2Cl2 has the smallest amount of moles.

For 5 moles Hg2Cl2 ( 0.0106 mol) we need 0.0106 / (5/2) = 0.00424 mol KMnO4

For 5 moles Hg2Cl2 we need (16/5) *0.0106 = 0.03392 moles of HCl

So the limiting reactant is Hg2Cl2.

Step 4: Calculate moles of product produced:

2*0.0106 = 0.0212 moles of HgCl2

(2/5) * 0.0106 = 0.00424 moles of MnCl2 and 0.00424 moles of KCl

(8/5) * 0.0106 = 0.01696 moles H2O

7 0
3 years ago
If 17.4 mL of 0.800 M HCl solution are needed to neutralize 5.00 mL of a household ammonia solution, what is the molar concentra
Verizon [17]
NH3  +HCl  ---->  NH4Cl

moles   of  HCl  used =    (0.8  x  17.4) /1000=  0.0139 moles
by  use   of reacting  ratio  between  HCl  to   NH4Cl    which is 1:1    therefore  the  moles   of  NH4Cl  is  also  =  0.0139 moles
molar   concentration  =  moles  /volume  in  liters 

molar  concentration  is  therefore=    (0.0139/5)  x1000 =  2.7 M
8 0
3 years ago
Read 2 more answers
Would the chlorine atom or ion be larger?
Ivenika [448]

Answer:

Chlorine Ion

Explanation:

The chlorine ion is adding 1 valence electron in order to complete its outer most shell. It has a charge of 1- meaning it is adding an electron.

6 0
3 years ago
Which substances have AH = 0 kJ/mol
aniked [119]

Answer:

Oxygen, bromine, iron, helium

Explanation:

\Delta H^o_f is defined as the standard enthalpy of formation. By definition, the standard enthalpy of formation is equal to 0 kJ/mol for the substances in their standard states, that is, at room temperature and 1 atm pressure.

Simply speaking, looking at the substances given, we need to understand whether their states agree with what we expect to see at standard conditions (e. g., sodium is a metal, fluorine is a gas, bromine is a liquid at standard conditions). Those are substances consisting of just one type of atoms.

  • Firstly, oxygen is a gas at standard conditions and it is diatomic, so its \Delta H^o_f=0 kJ/mol.
  • Although nitrogen is a gas at standard conditions, it is diatomic, so \Delta H^o_f\neq 0 kJ/mol.
  • Water is a liquid at standard conditions, however, it consists of two types of atoms, hydrogen and oxygen, so \Delta H^o_f \neq 0 kJ/mol.
  • Bromine is a liquid at standard conditions, so \Delta H^o_f=0 kJ/mol.
  • Iron is a solid at standard conditions, it's a metal, so \Delta H^o_f=0 kJ/mol.
  • Helium is a gas at standard conditions, it belongs to noble gases, so \Delta H^o_f=0 kJ/mol.
  • Sulfur is a solid at room conditions, however, the conformation it has is S_8 and not S_6, so \Delta H^o_f\neq 0 kJ/mol.
7 0
3 years ago
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