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3 years ago

What is free-fall acceleration near earth's surface

2 answers:

7 0

Near Earth's surface, the distance between the object that is falling and the center of Earth does not change very much. Thus, the force given by the law of universal gravitation depends only on the mass of the object that is falling.

Oliga [24]3 years ago

4 0

Free fall is when the only force acting on an object is gravity

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What is sound energy?

Natali5045456 [20]

Answer:

Explanation:

Because of the vibration

5 0

2 years ago

Read 2 more answers

The ideal gas law equation is: PV = nRT

nignag [31]

Answer:

The answer is the first option 0.37 moles

Explanation:

the ideal gas law is PV = nRT, so in the terms of n,

n = PV/RT (divide both sides by RT to let n stand alone)

given: P = 700 kpa, V = 2L, T = 450 K , R = 8.31

n = (700 * 2) / (8.31 * 450)

= 1400/3739.5

= 0.34

8 0

3 years ago

What is the energy of a photon with the frequency of 1.02 x 1015 Hz? Please show your work!

galben [10]

E = h v where v = frequency h = plancks constant 6.626 * 10 - 34

4.8 * 6.626 = 31.8

7 0

3 years ago

Why is potasium oxide not used to investigate property of hydrogen gas

Anarel [89]

Because potassium is more reactive than hydrogen

3 0

3 years ago

Determine the expected diffraction angle for the first-order diffraction from the (111) set of planes for FCC nickel (Ni) when m

faust18 [17]

Answer:

56°

Explanation:

First calculate $a:$

$a=2 R \sqrt{2}=2(0.1246) \sqrt{2}=0.352 \mathrm{nm}$

The interplanar spacing can be calculated from:

$d_{111}=\frac{a}{\sqrt{1^{2}+1^{2}+1^{2}}}=\frac{0.352}{\sqrt{3}}=0.203 \mathrm{nm}$

The diffraction angle is determined from:

$\sin \theta=\frac{n \lambda}{2 d_{111}}=\frac{1(0.1927)}{2(0.2035)}=0.476$

Solve for $\theta$

$\theta=\sin ^{-1}(0.476)=28^{\circ}$

The diffraction angle is:

$2 \theta=2\left(28^{\circ}\right)=56^{\circ}$

4 0

3 years ago