Given :
Walk in forward direction is 30 m .
Walk in backward direction is 25 m .
To Find :
The distance and displacement .
Solution :
We know , distance is total distance covered and displacement is distance between final and initial position .
So , distance travelled is :
D = 30 + 25 m = 55 m .
Now , we first move 30 m in forward direction and then 25 m in backward direction .
So , displacement is :
D = 30 - 25 m = 5 m .
Therefore , distance and displacement covered is 55 m and 5 m respectively .
Hence , this is the required solution .
The distance the object willl fall durring the 2nd seconds is 4.9 m
<h3>Data obtained from the question</h3>
The following data were obtained from the question:
- Initial velocity (u) = 0 m/s
- Acceleration due to gravity (g) = 9.8 m/s²
- Time (t) = 2 - 1 = 1 s
- Height (h) =?
<h3>How to determine the distance the object will fall during the 2nd seconds</h3>
The distance the object will fall during the 2nd seconds can be obtained as follow:
h = ut + ½gt²
h = (0 × 1) + (½ × 9.8 × 1²)
h = 0 + 4.9
h = 4.9 s
Thus, the distance the object will during the 2nd seconds is 4.9 m
Learn more about motion under gravity:
brainly.com/question/22719691
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