B precipitation,condensation,precipitation
The maximum height to which the ball attain before falling back down is 1147.96 m
<h3>Data obtained from the question</h3>
The following data were obtained from the question:
- Initial velocity (u) = 150 m/s
- Final velocity (v) = 0 m/s (at maximum height)
- Acceleration due to gravity (g) = 9.8 m/s²
- Maximum height (h) =?
<h3>How to determine the maximum height </h3>
The maximum height reached by the ball can be obtained as illustrated below:
v² = u² – 2gh (since the ball is going against gravity)
0² = 150² – (2 × 9.8 × h)
0 = 22500 – 19.6h
Collect like terms
0 – 22500 = –19.6h
–22500 = –19.6h
Divide both side by –19.6
h = –22500 / –19.6
h = 1147.96 m
Thus, the maximum height reached by the ball is 1147.96 m
Learn more about motion under gravity:
brainly.com/question/22719691
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Answer:
The power dissipated in the 3 Ω resistor is P= 5.3watts.
Explanation:
After combine the 3 and 6 Ω resistor in parallel, we have an 2 Ω and a 4 Ω resistor in series.
The resultating resistor is of Req=6Ω.
I= V/Req
I= 2A
the parallel resistors have a potential drop of Vparallel=4 volts.
I(3Ω) = Vparallel/R(3Ω)
I(3Ω)= 1.33A
P= I(3Ω)² * R(3Ω)
P= 5.3 Watts
Answer:
Ep = 0.6095 [J]
Explanation:
As defined in the problem statement, potential energy is defined as the product of mass by gravity by height. But first we must convert all the values given to measures of the international system (SI)
g = gravity = 10 [m/s^2]
h = elevation = 40 [ft] = 12.19 [m]
m = mass = 5 [g] = 0.005 [kg]
Ep = potential energy [J]
Ep = 0.005*10*12.19 = 0.6095 [J]
