Answer:
period of oscillations is 0.695 second
Explanation:
given data
mass m = 0.350 kg
spring stretches x = 12 cm = 0.12 m
to find out
period of oscillations
solution
we know here that force
force = k × x .........1
so force = mg = 0.35 (9.8) = 3.43 N
3.43 = k × 0.12
k = 28.58 N/m
so period of oscillations is
period of oscillations = 2π × ................2
put here value
period of oscillations = 2π ×
period of oscillations = 0.6953
so period of oscillations is 0.695 second
Answer:
We have to show surface area ,with few conditions that is by considering Force
and Pressure
to be respectively.
Explanation:
The atmospheric pressure is on Earth's surface.
The magnitude of the force exerted on a person by the atmosphere is .
Now to calculate surface area we can find it from and re-arranging it to.
So plugging the values,
Surface area
Hence from the above calculations we can say that surface area is .
So the surface area of an average person can be said to have , using the concept of pressure and force.