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dedylja [7]
2 years ago
5

A battery that warms while discharging

Physics
1 answer:
Arada [10]2 years ago
4 0
What is the question???
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Microwelds are formed where
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Between the bumps and dips of two surfaces. SO the answer is 2 surfaces. Hope this helps! :)

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3 years ago
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Describe the relationship between the length and period of a pendulum in the language of direct proportions
Wittaler [7]

The period of the pendulum is directly proportional to the square root of the length of the pendulum

Explanation:

The period of a simple pendulum is given by the equation

T=2\pi \sqrt{\frac{L}{g}}

where

T is the period

L is the length of the pendulum

g is the acceleration of gravity

From the equation, we see that when the length of the pendulum increases, the period of the pendulum increases as the square root of L, T\propto \sqrt{L}. This means that

The period of the pendulum is directly proportional to the square root of the length of the pendulum

From the equation, we also notice that the period of a pendulum does not depend on its mass.

#LearnwithBrainly

3 0
3 years ago
A scientist performs an experiment and asks other scientists around the
Arte-miy333 [17]

Answer: C

Explanation: I think

7 0
3 years ago
yellow cab taxi charges a $1.75 flat rate in addition to $0.65 per mile. kim has no more than $10 to spend on a ride. how many m
Nat2105 [25]

Answer:

you could go 12 miles paying $7.80 and $1.75

So in total being $9.55

5 0
2 years ago
An uncharged, nonconducting, hollow sphere of radius 10.0cm surrounds a 10.0-μC charge located at the origin of a Cartesian coor
MrMuchimi

The electric flux through the hole is 56.45\ webber .

  • Electric flux is the number of electric field lines cutting through the surface and is measured as surface intregal of electric field over that surface
  • Mathematically it is given by \phi_E=E.A \ Nm^2/C where E is the electric field and A is the area.
  • Gauss's law states that electric flux through closed surface is equal to the 1 / ε₀ times the charge enclosed by that surface which is given by  Ф = q / ε₀ where q is the central charge and ε₀ is the permittivity of the medium.

It is given , hollow sphere of radius 10.0cm surrounds a 10.0-μC charge.

The whole surface of hollow sphere = 4\pi r^2

                                                            = 4\times 3.14\times  (10 \times  10^{-2})^2 \\\\= 12.56\times 10^{-2} m^2

Area of the hole ( both side ) = 2\times \pi  r^2

                                               = 2\times 3.14 \times  (10^-^3)^2\\= 6.28 \times 10^-^6 m^2

According to Gauss's theorem, the flow from a particular charge in the center is given by

 \phi=  \frac{10\times10^-^6}{8.85\times 10^-^1^2}\\\\\phi=1.13\times10^6

This flux flows through the surface of the sphere, so the flux  per unit area which is given by

= \frac{ 1.13\times 10^6 }{ 12.56\times 10^-^2} \\\\= 8.99 \times 10^6 \  weber / m^2

Flux through area of hole is given by :

=  8.99\times10^6 \times6.28 \times 10^-^6\\ = 56.45 \ weber

Learn about more electric flux here :

brainly.com/question/26289097

#SPJ4

8 0
2 years ago
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