A battery that warms while discharging

What would the final volume of 40 L of gas at 80 pascals be if the pressure increases to 130 pascals?

melomori [17]

Answer:

Final volume, V2 = 24.62 L

Explanation:

Given the following data;

Initial volume = 40 L

Initial pressure = 80 Pa

Final pressure = 130 Pa

To find the final volume V2, we would use Boyles' law.

Boyles states that when the temperature of an ideal gas is kept constant, the pressure of the gas is inversely proportional to the volume occupied by the gas.

Mathematically, Boyles law is given by;

$PV = K$

$P_{1}V_{1} = P_{2}V_{2}$

Substituting into the equation, we have;

$80 * 40 = 130V_{2}$

$3200 = 130V_{2}$

$V_{2} = \frac {3200}{130}$

$V_{2} = 24.62$

Final volume, V2 = 24.62 Liters

5 0

2 years ago

When you approach a yield sign, while trying to enter or merge onto another road, traffic already on that road has the right of

kogti [31]

TRUE. When you approach a yield sign, while trying to enter or merge onto another road, traffic already on that road has the right of way.

5 0

2 years ago

Read 2 more answers

sara and tory are out fishing on the lake on a hot summer day when they both decide to go for a swim. sara dives off the front o

crimeas [40]

Here it is an application of Newton's III law

as we know by Newton's III law that every action has equal and opposite reaction

So here as we know that two boys jumps off the boat with different forces

from front side of the boat the boy jumps off with force 45 N which means as per Newton's III law if boy has a force of 45 N in forward direction then he must apply a reaction force on the boat in reverse direction of same magnitude

So boat must have an opposite force on front end with magnitude 45 N

Now similar way we can say

from back side of the boat the boy jumps off with force 60 N which means as per Newton's III law if boy has a force of 60 N in backward direction then he must apply a reaction force on the boat in reverse direction of same magnitude

So boat must have an opposite force on front end with magnitude 60 N

So here net force due to both jump on the boat is given by

$F_{net} = F_1 - F_2$