Answer:
yes, it is
Explanation:
The sequence: (+4)
23,27,31,35,39,43,47,51,55,59,63,67,71,75,79,83
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Answer:
(a) Calculate the field, armature, and load currents versus load = 306A
(b) Determine the terminal voltage at no-load and at rated load conditions = 300V
(c) Calculate the voltage regulation of the generator. Use the no-load voltage as the base value = 6.67%
(d) Plot the terminal voltage as a function of the load. Determine the load that corresponds to a 5% voltage drop using the no-load voltage as the base = 294.74V
Explanation:
CHECK THE ATTACHED FILES FOR DETAILED EXPLANATION.
Answer:
126984 cycles
Explanation:
Given data :
Sut = 530 MPa
f = 0.9
fully corrected Se = 210 MPa
using Miner's method attached below is the detailed solution of the given problem
when loaded with ± 225 MPa the number of cycles before it fails will be
≈ 126984
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