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Zepler [3.9K]
3 years ago
13

Compound A is an alkene that was treated with ozone to yield only (CH3CH2CH2)2C=O. Draw the major product that is expected when

compound A is treated with a peroxy acid (RCO3H) followed by aqueous acid (H3O+).

Chemistry
1 answer:
DochEvi [55]3 years ago
3 0

Answer:

2,2,3,3-tetrapropyloxirane

Explanation:

In this case, we have to know first the alkene that will react with the peroxyacid. So:

<u>What do we know about the unknown alkene? </u>

We know the product of the ozonolysis reaction (see figure 1). This reaction is an <u>oxidative rupture reaction</u>. Therefore, the double bond will be broken and we have to replace the carbons on each side of the double bond by oxygens. If (CH_3CH_2CH_2)_2C=O is the only product we will have a symmetric molecule in this case 4,5-dipropyloct-4-ene.

<u>What is the product with the peroxyacid?</u>

This compound in the presence of alkenes will produce <u>peroxides.</u> Therefore we have to put a peroxide group in the carbons where the double bond was placed. So, we will have as product <u>2,2,3,3-tetrapropyloxirane.</u> (see figure 2)

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Deffense [45]
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Answer 2) The same would be observed in this case, if we replace HNO_{3} with HCl it will shift the equilibrium to the right as their will be generation of AgCl as the precipitate.

As per the definition of Le Chatelier's principle if we add reactants in the reaction the equilibrium will tend to move towards right, also if we replace the products or remove it then too it will shift the equilibrium towards right. So, in this reaction you are removing Ag^{+} and Cl^{-} ions from the solution.
7 0
3 years ago
What term describes a carbon atom that has four different groups bonded to it?
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Non-<span>superimposable:
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Polarized Light and Chiral Carbon:
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8 0
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Answer:

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So, preparing the 1/10 or ten percent solution is where adding 10 ml of bleach which is diluted to 90 ml clean water. This diluted solution can be use as disinfecting solution.

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3 years ago
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Answer:

It's

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(I was also doing same qn)

7 0
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