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IRISSAK [1]
4 years ago
7

Intrapulmonary pressure is the _______________________.

Physics
1 answer:
lisabon 2012 [21]4 years ago
4 0
Intrapulmonary pressure is the pressure within the lungs
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A student pulls a cart across a horizontal floor by exerting a force of 50 newton at an angle 30
ivann1987 [24]
What's the question to this
6 0
4 years ago
What is the magnetic force on a 200 cm length of (straight) wire carrying a current of 30 A in a region where a uniform magnetic
Bezzdna [24]

Answer:

F = 0.112 N

Explanation:

To find the magnitude of magnetic force on the wire, you use the following formula:

|\vec{F}|=|i\vec{L}\ X\ \vec{B}|=iLBsin\theta   (1)

L: length of the wire = 200cm = 0.2m

i: current in the wire = 30 A

B: magnitude of the magnetic field = 0.055 T

θ: angle between the directions of L and B = 20°

You replace the values of L, i, B and θ in the equation (1):

|\vec{F}|=(30A)(0.2m)(0.055T)sin(20\°)=0.112N

hence, the magnetic force on teh wire is 0.112N

3 0
3 years ago
1pt In conduction, thermal energy naturally flows
Damm [24]

Answer:

A. from a low-temperature areas to high-temperature areas

Explanation:

it goes from low-temperature to high-temperature because it's reacting

3 0
3 years ago
I NEED THE ANSWER ASAP I GIVE THANKS + 5 STARS
Kobotan [32]
Work or energy spent=force times distance=25N*4m=100Nm
power=energy or work divided by time=100Nm/5s=20Nm/s
5 0
4 years ago
The length and width of a rectangular room are measured to be 3.92 ± 0.0035 m and 3.15 ± 0.0055 m. In this problem you can appro
Pavel [41]

Answer:

A)A=12.2480\ m^2

B)12.2480\pm 0.1029\ m^2

Explanation:

<u>Given:</u>

Length of the room l= 3.92 ± 0.0035

Width of the room w= 3.15 ± 0.0055

A) Let A be the area of the room

A=l\times w\\A=3.92\times3.15\\A=12.2480\ \rm m^2

B)We will calculate uncertainty in each dimension

%uncertainty in length=\dfrac{0.0035}{3.92}\times 100=0.0892\ %

%uncertainty in width =\dfrac{0.0055}{3.15}\times 100=0.0174%

The uncertainty in area will be sum of uncertainty in length and width

%uncertainty in Area=  %uncertainty in length + %uncertainty in width

%uncertainty in Area=0.0892\ % + 0.0174\ %

%uncertainty in Area=0.0106

Uncertainty in Area=0.0106\times 12.2480=0.1029\ \rm m^2

There Area is12.2480 ± 0.1029\ \rm m^2

7 0
3 years ago
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