A sound wave leaves the loudspeaker. As it travels, it experiences a temporary increase in wavelength and then returns to its or
iginal wavelength. Which of the following scenarios could explain this change in wavelength? Select ALL that apply.
A
The sound wave traveled into the rocky ground.
B
The sound wave traveled through a glass of water.
C
The sound wave reflected off of a rock wall nearby.
D
The sound wave traveled through a person walking along the shore.
E
The sound wave traveled through a helium balloon (helium is less dense than air).
A
The sound wave traveled into the rocky ground.
B
The sound wave traveled through a glass of water.
C
The sound wave reflected off of a rock wall nearby.
D
The sound wave traveled through a person walking along the shore.
E
The sound wave traveled through a helium balloon (helium is less dense than air).
1 answer:
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Answer:
d = 90 ft
Explanation:
Here in each swing the distance sweeps by the swing is half of the initial distance that it will move
So here we can say that total distance in whole motion is given as
since it is half of the distance that it will move in each swing so it would be a geometric progression with common ratio of 1/2
so sum of such GP is given by the formula
Answer:0.0704 kg
Explanation:
Given
initial Absolute pressure=210+101.325=311.325
as the volume remains constant therefore
therefore Gauge pressure is 337.44-101.325=236.117 KPa
Initial mass
Final mass
Therefore =0.91-0.839=0.0704 kg of air needs to be removed to get initial pressure back
Answer
given,
wavelength (λ)= 500 n m
thickness of film= 10⁻⁴ cm
refractive index = μ = 1.375
distance traveled is double which is equal to 2 x 10⁻⁴ cm
a) Number of wave
N = 2.91
N = 3
b) phase difference is equal to
Reflection from the first surface has a 180° (½λ) phase change.
There is no phase change for the 2nd surface reflection and there is no phase difference for the 2nd wave having traveled an exact whole number of waves.
net phase difference =
= 270°