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Nina [5.8K]
2 years ago
7

A sound wave leaves the loudspeaker. As it travels, it experiences a temporary increase in wavelength and then returns to its or

iginal wavelength. Which of the following scenarios could explain this change in wavelength? Select ALL that apply.
A
The sound wave traveled into the rocky ground.

B
The sound wave traveled through a glass of water.

C
The sound wave reflected off of a rock wall nearby.

D
The sound wave traveled through a person walking along the shore.

E
The sound wave traveled through a helium balloon (helium is less dense than air).

Physics
1 answer:
Brut [27]2 years ago
4 0

A sound wave leaves the loudspeaker. As it travels, it experiences a temporary increase in wavelength and then returns to its original wavelength.  The sound wave traveled through a helium balloon (helium is less dense than air could explain this change in wavelength

The pattern of disruption brought on by energy moving away from the sound source is known as a sound wave. Longitudinal waves are what makeup sound. This indicates that the direction of energy wave propagation and particle vibrational propagation are parallel. The atoms oscillate when they are put into vibration.

A high-pressure and a low-pressure zone are created in the medium as a result of this constant back and forth action. Compressions and rarefactions, respectively, are terms used to describe these high- and low-pressure zones. The sound waves go from one medium to another as a result of these regions being transmitted to the surrounding media.

To learn more about sound waves please visit -
brainly.com/question/11797560
#SPJ1

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A force of 1.200×103 N pushes a man on a bicycle forward. Air resistance pushes against him with a force of 615 N. If he starts
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15.45 m/s

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F = 1.2 x 10^3 N, Fk = 615 N, u = 0, s = 25 m

Let the speed after traveling 25 m is v.

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4 0
3 years ago
Juan is on a morning jog. His speed is represented in the graph. At what rate of speed is Juan running between 4min and 6min? Ac
Nesterboy [21]

Answer:

<em>a) The speed of Juan is 250 m/min </em>

<em>b) In that interval, he's at rest </em>

<em>c) Juan would have needed 12 minutes to run 3000 m</em>

Explanation:

<u>Distance vs Time Graph Analysis </u>

If time is on the horizontal axis, and the distance is in the vertical axis, then the slope of the graph represents the instantaneous speed of the moving object. The graph shows three different zones which reflect Juan's jogging at that morning.

a) The period between 4 and 6 minutes clearly shows Juan is moving in such a way the distance increases when time passes. The speed of the motion can be obtained by computing the slope of the line. We can locate the points (4,1000) and (6,1500). We compute the speed  

\displaystyle v=\frac{1500-1000}{6-4}=\frac{500}{2}=250 m/min

The speed of Juan is 250 m/min

b) We can see between 7 and 11 minutes, Juan's distance is not changing because he stopped running. In that interval, he's at rest

c) We have already determined the speed on the first 7 minutes (the same as between 4 and 6 minutes). We know that

\displaystyle v=\frac{x}{t}

Where v is the speed, x is the distance, and t is the time

We need to know the time needed to travel x=3000 m at the initial speed v=250 m/min, so we solve the equation for t

\displaystyle t=\frac{x}{v}

\displaystyle t=\frac{3000}{250}=12\ minutes

Juan would have needed 12 minutes to run 3000 m

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4 years ago
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