C+2H2 -------> CH4
from reaction 2 mol 1 mol
from the problem x mol 10 mol
x=2*10/1 = 20 mol
Answer: 20 mol of H2.
The amount of carbon combined with oxygen in order to form Carbon Dioxide(CO₂) is 12 grams
The Law of Multiple proportions is one of the basic laws in chemistry along with the Law of Definite proportion. This law was proposed by John Dalton in 1803. The law states that if two elements react to form one or more compounds then the ratio of masses of both the elements is in the ratio of small whole numbers.
It is known that Carbon can form two different compounds while reacting with Oxygen that is: Carbon Monoxide, Carbon Dioxide. For Carbon Monoxide, 12g of Carbon needs to react with 16g of Oxygen. Whereas, In Carbon Dioxide, 12g of Carbon needs to react with 32g of Oxygen. So the mass of Carbon is equal in both cases is 12g.
C(12g) + O(16g) ⇒ CO (Carbon Monoxide)
C(12g) + 2O(32g) ⇒ CO₂ (Carbon Dioxide)
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C₈H₁₈ + F₂ -----hV----> C₈H₁₇F + HF
The acid dissociation constant is defined as Ka = [H+][A-]/[HA] where [H+], [A-] and [HA] are the concentrations of protons, conjugate base, and acid in solution respectively. Assuming this is a weak acid as the pH is quite high for a 1.35 M solution, we can assume that the change in [HA] is negligible and therefore [HA] = 1.35 M.
To calculate [H+] we can use the relationship pH = -log[H+], rearranging to give: [H+] = 10^(-pH) = 10^(-2.93) = 1.17 x 10^(-3).
Since the acid is relatively concentrated we can assume therefore that [H+] = [A-] as for each proton dissociated, a conjugate base is formed.
Therefore, we can calculate Ka as:
Ka = [H+]^2/[HA] = (1.17 x 10^-3 M)^2/1.35 = 1.01 x 10^-6 M
The answer is true all living things are called organisms
