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3 years ago

When can a car have no acceleration but still be moving

Physics

2 answers:

gregori [183]3 years ago

5 0

Answer:

A. A car can still be moving without acceleration when it has some velocity.

B. A car can come to a stop when moving itself when it has some de acceleration.

C.A ca can start at 0 m/s and speed up to 15 m/s when it has some acceleration.

Explanation:

A. since the car has no acceleration the velocity of the car would help it moving.

B. when the car is moving with some velocity but coming to a stop this is possible of and only if it has some de acceleration

C. since the speed of the car increases from 0 to 15 m/s acceleration is involved. If the speed was constant there would be no acceleration involved.

mylen [45]3 years ago

3 0

Answer:

When the velocity of the car is constant.

Explanation:

A car moving with no acceleration possesses a uniform velocity i.e the car velocity is not changing. This means that the car is covering a distance at a particular time interval "on a straight line". The velocity of the car is constant at that point that it has no acceleration because for a body to accelerates, the velocity of the body must be changing i.e the final velocity and the initial velocity must be different.

If the initial and final velocity of a body is the same, this means that the body is moving with a constant velocity and as such not accelerating.

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3 years ago

During a baseball game, a batter hits a high pop-up. If the ball remains in the air for 6.22 s, how high does it rise? The accel

BigorU [14]

Answer:

47.4 m

Explanation:

When an object is thrown upward, it rises up, it reaches its maximum height, and then it goes down. The time at which it reaches its maximum height is half the total time of flight.

In this case, the time of flight is 6.22 s, so the time the ball takes to reach the maximum height is

$t=\frac{6.22}{2}=3.11 s$

Now we consider only the downward motion of the ball: it is a free fall motion, so we can find the vertical displacement by using the suvat equation

$s=ut+\frac{1}{2}gt^2$

where

s is the vertical displacement

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Solving the formula, we find

$s=\frac{1}{2}(9.8)(3.11)^2=47.4 m$

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3 years ago

If a nearsighted person has a far point df that is 3.50m from the eye, what is the focal length f1 of the contact lenses that th

olga55 [171]

Answer:

f1= -350cm or -3.5m

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Explanation:

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Answer:

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