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3 years ago

When can a car have no acceleration but still be moving

Physics

2 answers:

gregori [183]3 years ago

5 0

Answer:

A. A car can still be moving without acceleration when it has some velocity.

B. A car can come to a stop when moving itself when it has some de acceleration.

C.A ca can start at 0 m/s and speed up to 15 m/s when it has some acceleration.

Explanation:

A. since the car has no acceleration the velocity of the car would help it moving.

B. when the car is moving with some velocity but coming to a stop this is possible of and only if it has some de acceleration

C. since the speed of the car increases from 0 to 15 m/s acceleration is involved. If the speed was constant there would be no acceleration involved.

mylen [45]3 years ago

3 0

Answer:

When the velocity of the car is constant.

Explanation:

A car moving with no acceleration possesses a uniform velocity i.e the car velocity is not changing. This means that the car is covering a distance at a particular time interval "on a straight line". The velocity of the car is constant at that point that it has no acceleration because for a body to accelerates, the velocity of the body must be changing i.e the final velocity and the initial velocity must be different.

If the initial and final velocity of a body is the same, this means that the body is moving with a constant velocity and as such not accelerating.

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Suppose oil spills from a ruptured tanker and spreads in a circular pattern. If the radius of the oil spill increases at a const

Dafna1 [17]

Answer:

$\frac{dA}{dt} = 188.5 m^2/s$

Explanation:

As we know that area of the circle at any instant of time is given as

$A = \pi r^2$

now in order to find the rate of change in area we will have

$\frac{dA}{dt} = 2\pi r\frac{dr}{dt}$

here we know that

rate of change of radius is given as

$\frac{dr}{dt}= 1 m/s$

radius of the circle is given as

$r = 30 m$

now we have

$\frac{dA}{dt} = 2\pi (30)(1)$

$\frac{dA}{dt} = 60\pi$

$\frac{dA}{dt} = 188.5 m^2/s$

8 0

4 years ago

The outside air pressure changes from 1.0 atm to 1.1 atm. The mass density of mercury is 13,534 kg/m3.By how much does mercury i

mezya [45]

Answer:

The mercury in the barometer rises by a height of 0.0764 m = 76.4 cm = 764 mm

Explanation:

The change in pressure is related to the density of fluid and height risen by the fluid through the relation

ΔP = ρgh

ΔP = change in pressure = P₂ - P₁ = 1.1 - 1.0 = 0.1 atm = 0.1 × 101325 Pa = 10132.5 Pa

ρ = density of the fluid = 13,534 kg/m³

g = acceleration due to gravity = 9.8 m/s²

h = height through which the mercury in barometer rises = ?

10132.5 = 13534 × 9.8 × h

h = (10132.5) ÷ (13534 × 9.8)

h = 0.0763948996 = 0.0764 m = 76.4 cm = 764 mm

Hope this Helps!!!

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4 years ago

What produces virtual and real images

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Virtual images are produced when rays of a light (after reflection or refraction) appear to meet a a certain point. While real images are produced when rays of a light (after reflection or refraction) meet at some point.

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Answer:

The law of conservation of momentum states that, in the absence of an external force, the momentum of a system remains unchanged.

Explanation:

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