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Anvisha [2.4K]
3 years ago
5

A net torque applied to an object causes __________. A net torque applied to an object causes __________. the angular velocity o

f the object to change the object to rotate at a constant rate a linear acceleration of the object the moment of inertia of the object to change
Physics
1 answer:
matrenka [14]3 years ago
7 0

Answer:

A net torque applied to an object causes the angular velocity of the object to change.

Explanation:

The rotational equivalence of force is called a Torque. Thus, a net torque will make an object to rotate with an angular acceleration. Due tothe fact that all rotational motions have an axis of rotation, then a torque must be defined about a rotational axis. A force applied to a point on an object about the axis of rotation is known as a torque.

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Here we have a simple matter of conservation of energy. ME=PE+KE.

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A police officer is using her radar to check speeds. She is moving south at 50 mph. You are moving
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3 years ago
A protostar is _____.
defon

<u>Answer</u>

5.the stage before a star becomes a main sequence star

<u>Explanation</u>

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Read 2 more answers
If the velocity of a pitched ball has a magnitude of 44.5 m/sm/s and the batted ball's velocity is 55.5 m/sm/s in the opposite d
Yuliya22 [10]

Incomplete question as the mass of baseball is missing.I have assume 0.2kg mass of baseball.So complete question is:

A baseball has mass 0.2 kg.If the velocity of a pitched ball has a magnitude of 44.5 m/sm/s and the batted ball's velocity is 55.5 m/sm/s in the opposite direction, find the magnitude of the change in momentum of the ball and of the impulse applied to it by the bat.

Answer:

ΔP=20 kg.m/s

Explanation:

Given data

Mass m=0.2 kg

Initial speed Vi=-44.5m/s

Final speed Vf=55.5 m/s

Required

Change in momentum ΔP

Solution

First we take the batted balls velocity as the final velocity and its direction is the positive direction and we take the pitched balls velocity as the initial velocity and so its direction will be negative direction.So we have:

v_{i}=-44.5m/s\\v_{f}=55.5m/s

Now we need to find the initial momentum

So

P_{1}=m*v_{i}

Substitute the given values

P_{1}=(0.2kg)(-44.5m/s)\\P_{1}=-8.9kg.m/s

Now for final momentum

P_{2}=mv_{f}\\P_{2}=(0.2kg)(55.5m/s)\\P_{2}=11.1kg.m/s

So the change in momentum is given as:

ΔP=P₂-P₁

=[(11.1kg.m/s)-(-8.9kg.m/s)]\\=20kg.m/s

ΔP=20 kg.m/s

3 0
3 years ago
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