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Anvisha [2.4K]
3 years ago
5

A net torque applied to an object causes __________. A net torque applied to an object causes __________. the angular velocity o

f the object to change the object to rotate at a constant rate a linear acceleration of the object the moment of inertia of the object to change
Physics
1 answer:
matrenka [14]3 years ago
7 0

Answer:

A net torque applied to an object causes the angular velocity of the object to change.

Explanation:

The rotational equivalence of force is called a Torque. Thus, a net torque will make an object to rotate with an angular acceleration. Due tothe fact that all rotational motions have an axis of rotation, then a torque must be defined about a rotational axis. A force applied to a point on an object about the axis of rotation is known as a torque.

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Hoochie [10]

Answer:

Because of the frictional force, the net force will oppose direction of the block and be directed towards the left even tho the spring exerts no force at this point

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Whais the cause of necular bomb ​
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Answer:

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Explanation:

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2 years ago
Elements in the periodic table are arranged in order of increasing...
Sauron [17]

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2 years ago
You pull with a force of 77 N on a piece of luggage of mass 23 kg, but it does
Vinvika [58]

Answer:

The force of static friction acting on the luggage is, Fₓ = 180.32 N

Explanation:

Given data,

The mass of the luggage, m = 23 kg

You pulled the luggage with a force of, F = 77 N

The coefficient of static friction of luggage and floor, μₓ = 0.8

The formula for static frictional force is,

                                      Fₓ = μₓ · η

Where,

                                  η - normal force acting on the luggage 'mg'

Substituting the values in the above equation,

                                   Fₓ = 0.8 x 23 x 9.8

                                        = 180.32 N

Hence, the minimum force require to pull the luggage is, Fₓ = 180.32 N

5 0
4 years ago
Read 2 more answers
Consider a metal single crystal oriented such that the normal to the slip plane and the slip direction are at angles of 60 and 3
Scilla [17]

Explanation:

Given that,

Angle by the normal to the slip α= 60°

Angle by the slip direction with the tensile axis β= 35°

Shear stress = 6.2 MPa

Applied stress = 12 MPa

We need to calculate the shear stress applied at the slip plane

Using formula of shear stress

\tau=\sigma\cos\alpha\cos\beta

Put the value into the formula

\tau=12\cos60\times\cos35

\tau=4.91\ MPa

Since, the shear stress applied at the slip plane is less than the critical resolved shear stress

So, The crystal will not yield.

Now, We need to calculate the applied stress necessary for the crystal to yield

Using formula of stress

\sigma=\dfrac{\tau_{c}}{\cos\alpha\cos\beta}

Put the value into the formula

\sigma=\dfrac{6.2}{\cos60\cos35}

\sigma=15.13\ MPa

Hence, This is the required solution.

3 0
3 years ago
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