All categories

3 years ago

What is the scariest thing to established U.S. utilities?

Physics

2 answers:

iogann1982 [59]3 years ago

6 0

<span>They are still structured as monopolies that bundle together disparate energy </span>

murzikaleks [220]3 years ago

4 0

im sorry i dont know

You might be interested in

In an experiment performed in a space station, a force of 60 N causes an object to have an acceleration equal to 4m/s. What is t

Naddik [55]

I'm afraid you're not paying attention. This question is loaded with
all the important words, and you don't recognize Newton's second
law of motion. Didn't you notice the "force", "acceleration", and
"mass" all over the place in there ?

Newton's 2nd law: Force = (mass) x (acceleration)

The answer is going to be 'mass', so let's divide
each side of Newton's law by 'acceleration':

   Mass = (force) / (acceleration)

Now, just write in the numbers that the question gave you:

      force = 60 newtons
   acceleration = 4 m/s²

Here's the equation again:    Mass = (force) / (acceleration)

   = (60 N) / (4 m/s²)

   = 15 kg .

3 0

4 years ago

Physics I need help :(

kvv77 [185]

The correct answer is C july-september plz mark as brainliest!

7 0

4 years ago

A snow ball is thrown upward at a speed of 27 m/s. How high is the snow ball 3.5 seconds later? Also, how fast is it moving at t

JulijaS [17]

Answer:

Dy = 111.66 [m]

t = 3.5 [s]

Explanation:

To solve this problem we must use the equations of kinematics.

$v_{f} = v_{o} - (g*t)\\$

where:

Vf = final velocity [m/s]

Vo = initial velocity = 27 [m/s]

g = gravity acceleration = 9.81 [m/s²]

t = time = 3.5 [s]

Note: The negative sign of the equation means that the gravity acceleration goes in opposite direction

Vf = 27 - (9,81*3,5)

Vf = - 7.33 [m/s] (this negative sign indicates that at this moment the snowball is going downwards)

To find how high the snowball was we must use the following equation:

$Dy=v_{o} *t+\frac{1}{2}*g*t$

Dy = (27*3.5) + (0.5*9.81*3.5)

Dy = 94.5 + (17.16)

Dy = 111.66 [m]

5 0

4 years ago

If a rocket transfers 2,500,000 MJ of energy when it takes off, how much work is done?

erastovalidia [21]

Answer:

2,500,000 MJ ( $2.5\cdot 10^6 J$ )

Explanation:

According to the work-energy theorem:

The work done on an object is equal to the amount of energy transferred

In this problem, the energy transferred by the rocket is

$E=2,500,000 MJ=2.5\cdot 10^6 J$

Therefore, the work done must be equal to the energy transferred, therefore:

$W=E=2.5\cdot 10^6 J$

6 0

3 years ago

in an experiment the following readings were observed volume of alcohol flowing per minute equals to 10 raise to power - 5 cube

tekilochka [14]

Answer:

The viscosity is 1.30 x 10^-3 deca poise.

Explanation:

Volume per minute, V = 10^-5 m^3

Volume per second, V = 1.67 x 10^-7 m^3

density, d = 800 kg/m^3

radius, r = 0.05 cm

Length, L = 0.5 m

Height, h = 60 cm

Pressure, P = h d g = 0.6 x 800 x 9.8 = 4704 Pa

Use the formula of rate of flow

$V = \frac{\pi p r^4}{8\eta L}\\\\1.67\times 10^{-7}\times8\times \eta\times 0.5 = 3.14\times 4707\times (0.05\times 10^{-2})^4\\\\\eta = 1.38\times 10^{-3} deca poise$

6 0

3 years ago