Acceleration = V^2/r = 18^2/ 30 = 10.8 m/s^2
Answer:
From 9 to 10 sec the velocity is decreasing at a constant rate.
Change in V = 20 m/s - 30 m/s = -10 m/s
Since acceleration is constant from point E to point F (straight line)
and t = 9.5 sec is on this line
a = (20 m/s - 30 m/s) / 1 sec = -10 m/s^2
From km 240 to km 300 there are 60 km.
The time to travel 60 km at 80km/h is t = d/V = 60km / 80 km/h = 3/4 h.
That is 45 minutes. Then the car will arrive at 7:30 + 45 min = 8:15.
Power is the rate work is usually done in.
They are measured in joules, calories, and kilocalories
