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3 years ago

Which common characteristic of planets do Saturn and Earth share?

Physics

2 answers:

Mademuasel [1]3 years ago

8 0

I believe it’s
“they have thick atmospheres”
i hope i’m right and this helped you

sveta [45]3 years ago

7 0

Answer:they have thick atmospheres

Explanation:

That’s the only thing they have in common

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normally a slower moving person would develop less power then a faster moving person. describe a situation in which a slower mov

belka [17]

Answer:

muscle

Explanation:

weight can also be added by muscle. not necessarily fat. so if you have a lot of muscle so that adds weight you can be very powerful but can mover very slow.

4 0

3 years ago

A steel ring is 50mm diameter and 2mm thick. it must be fitted onto a shaft 50.04 mm diameter. calculate the temperature to whic

MAVERICK [17]

The temperature to which it must be heated in order to fit the shaft is 73.33 ⁰C.

<h3>Linear expansivity </h3>

The temperature to which it must be heated in order to fit the shaft is calculated as follows;

$\frac{\Delta L}{L} = \alpha \Delta T\\\\\Delta T = \frac{\Delta L}{\alpha L}$

where;

ΔT is change in temperature
ΔL is change in length = 50.04 mm - 50 mm = 0.04 mm
α is coefficient of linear expansion
L is original length

ΔT = (0.04)/(50 x 15 x 10⁻⁶)

ΔT = 53.3 ⁰C

<h3>Final temperature</h3>

T₂ - T₁ = ΔT

T₂ = ΔT + T₁

where;

T₂ is final temperature
T₁ is initial temperature

T₂ = 53.3 + 20

T₂ = 73.33 ⁰C

Learn more about linear expansivity here: brainly.com/question/14325928

#SPJ1

4 0

2 years ago

Horizontal circular motion questions:

NemiM [27]

1. D, constant
Force must be in the direction of the velocity to change speed.

2. B. to the center of the curvature
This allows the vehicle to complete the turn.

7 0

3 years ago

a ball is thrown straight up into the air with a speed of 13 m/s. if the ball has a mass of 0.25 kg, how high does the ball go?

evablogger [386]

<h2>Hello!</h2>

The answer is: 8.62m

There are involved two types of mechanical energy: kinetic energy and potential energy, in two different moments.

<h2>First moment:</h2>

Before the ball is thrown, where the potential energy is 0.

<h2>Second moment: </h2>

After the ball is thrown, at its maximum height, the Kinetic Energy turns to 0 (since at maximum height,the speed is equal to 0) and the PE turns to its max value.

Therefore,

$E=PE+KE$

Where:

$PE=m.g.h$

$KE=\frac{1*m*v^{2}}{2}$

<em>E</em> is the total energy

<em>PE</em> is the potential energy

<em>KE</em> is the kinetic energy

<em>m</em> is the mass of the object

<em>g</em> is the gravitational acceleration

<em>h </em>is the reached height of the object

<em>v</em> is the velocity of the object

Since the total energy is always constant, according to the Law of Conservation of Energy, we can write the following equation:

$KE_{1}+PE_{1}=KE_{2}+PE_{2}$

Remember, at the first moment the PE is equal to 0 since there is not height, and at the second moment, the KE is equal to 0 since the velocity at maximum height is 0.

$\frac{1*m*v^{2}}{2}+m.g.(0)=\frac{1*m*0^{2}}{2}+m.g.h\\\frac{1*m*v_{1} ^{2}}{2}=m*g*h_{2}$