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IgorLugansk [536]
3 years ago
15

g the space in between two glass sheets has a volume of 0.025 m3. If the temperature of the gas is 290 K, what is the rms speed

of the gas atoms
Physics
1 answer:
Keith_Richards [23]3 years ago
3 0

Complete Question

Argon gas (a monatomic gas) is sometimes used to insulate a double-pane window for purposes of insulation. In a particular window, the space in between two glass sheets has a volume of 0.025 \ m^3. If the temperature of the gas is 290 K. what is the rms speed of the gas atoms? The atomic mass of Argon is 39.9 u.(l u= 1.66x10-27 kg) Enter your answer in m/s

Answer:

The value is V_{rms} = 425.75 \  m/s

Explanation:

From the question we are told that

     The volume of the space in between the two glass sheet is  a =  0.025 \ m^3

     The temperature of the gas is T =  290 \  K

       The atomic mass of Argon is  m  = 39.9 \  u  =  39.9 * 1.66 *10^{-27} = 6.623 *10^{-26} \  kg

Generally the root mean square velocity is mathematically represented as

      V_{rms} =  \sqrt{\frac{3 K T}{ m } }

Here K is the Boltzmann constant  with value k  =  1.38 *10^{-23} \  m^3 \cdot kg \cdot s^{-2} \cdot K^{-1}

So

     V_{rms} =  \sqrt{\frac{3 *  1.38 *10^{-23} *  290 }{ 6.6234*10^{-26} } }

=>   V_{rms} = 425.75 \  m/s

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and where the surface is

A = 1.8 m^2

Substituting, we find

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