Question

A person has a reasonable chance of surviving an automobile crash if the deceleration is no more than 30 g’s.

Answer 1

Answer:

19129.5 N

1.1831 m

Explanation:

m = Mass of person = 65 kg

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration = 30g

g = Acceleration due to gravity = 9.81 m/s²

Force is given by

$F=ma\\\Rightarrow F=65\times 30\times 9.81\\\Rightarrow F=19129.5\ N$

The force on the person is 19129.5 N

$v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0^2-\left(95\times \dfrac{1000}{3600}\right)^2}{2\times -9.81\times 30}\\\Rightarrow s=1.1831\ m$

The distance traveled if brought to rest is 1.1831 m