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e-lub [12.9K]
2 years ago
14

Each byte contains 8 bits of information. Write an equation to represent the relationship between the number of packets and the

number of bits, where p represents the number of packets and x represents the number of bits. x= _____
Mathematics
1 answer:
shepuryov [24]2 years ago
7 0

Answer:8p

Step-by-step explanation:

Because their is 8 bits so x equals 8p I got p because the other equation on the problem was b = 1500p so we still using the same variable so p is the variable so 8p is the answer

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-12 is in the correct position, (x,y)

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Evaluate the expression 2v^3•v^0
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2v^3

Step-by-step explanation:

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Solve the Equation: √3x-12=0
konstantin123 [22]

√3x - 12 = 0

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Sveta_85 [38]

Translations, rotations, and reflections are all rigid transformations.

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3 years ago
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On a linear X temperature scale, water freezes at −115.0°X and boils at 325.0°X. On a linear Y temperature scale, water freezes
belka [17]

Answer:

The current temperature on the X scale is 1150 °X.

Step-by-step explanation:

Let is determine first the ratio of change in X linear temperature scale to change in Y linear temperature scale:

r = \frac{\Delta T_{X}}{\Delta T_{Y}}

r = \frac{325\,^{\circ}X-(-115\,^{\circ}X)}{-25\,^{\circ}Y - (-65.00\,^{\circ}Y)}

r = 11\,\frac{^{\circ}X}{^{\circ}Y}

The difference between current temperature in Y linear scale with respect to freezing point is:

\Delta T_{Y} = 50\,^{\circ}Y - (-65\,^{\circ}Y)

\Delta T_{Y} = 115\,^{\circ}Y

The change in X linear scale is:

\Delta T_{X} = r\cdot \Delta T_{Y}

\Delta T_{X} = \left(11\,\frac{^{\circ}X}{^{\circ}Y} \right)\cdot (115\,^{\circ}Y)

\Delta T_{X} = 1265\,^{\circ}X

Lastly, the current temperature on the X scale is:

T_{X} = -115\,^{\circ}X + 1265\,^{\circ}X

T_{X} = 1150\,^{\circ}X

The current temperature on the X scale is 1150 °X.

5 0
3 years ago
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