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LenKa [72]
3 years ago
14

Plz answer #2 plz this is 8th grade science / physics

Physics
1 answer:
MrRissso [65]3 years ago
5 0
All you need is your science book
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An acorn falls from a branch located 9.8 m above the ground. After 1 s of falling, the acorn's velocity will be 9.8 m/s downward
goldenfox [79]

Answer:

The acorn hasn't hit the ground because it only falsl half of the branch distance from the ground

Explanation:

given information:

h =9.8

t =1 s

g = 9.8

the average speed

v = 1/2 gt²

   = 1/2 (9.8) (1)²

   = 4.8 m/s

the distance in 1s

h = v t

   = 4.8 (1)

   = 4.8 m

the acorn hasn't hit the ground because it only falsl half of the branch distance from the ground

   =

8 0
3 years ago
the royal Gorge Bridge in Colorado rises 321 m above the Arkansas river. suppose you kick a rock horizontally off the bridge. Th
KengaRu [80]

Answer:

2.48 m/s

Explanation:

We can use the kinematic equation,

s = ut +½at²

Where

s = displacement

u = initial velocity

t = time taken

a = acceleration

Using the equation in vertical direction,

321 = 0×t +½×g×t², u = 0 because initial vertical velocity is 0

We get t = 8.01 s

Using the equation in the horizontal direction,

52 = u×8.01 +½×0×(8.01)²,. a = 0 because no unbalanced force act on object in that direction

So u = 2.48 m/s

5 0
3 years ago
A clock radio is rated as 30 w of power output. if the radio also draws 30 w at 120 v, which will the current draw be?
g100num [7]
P = IV

I = P/V =  30 / 120 = 0.25 A.

Current = 0.25A  
4 0
3 years ago
Which of the following does not have a global cycle?
Darya [45]
The answer is c hope it helps
8 0
3 years ago
Read 2 more answers
Consider one such cell where the magnitude of the potential difference is 65 mV, and the inner surface of the membrane is at a h
Gelneren [198K]

Answer: W = 1.04.10^{-20} J

Explanation: Since the potassium ion is at the outside membrane of a cell and the potential here is lower than the potential inside the cell, the transport will need work to happen.

The work to transport an ion from a lower potential side to a higher potential side is calculated by

W=q.\Delta V

q is charge;

ΔV is the potential difference;

Potassium ion has +1 charge, which means:

p = 1.6.10^{-19} C

To determine work in joules, potential has to be in Volts, so:

\Delta V=65.10^{-3}V

Then, work is

W=1.6.10^{-19}.65.10^{-3}

W=1.04.10^{-20}

To move a potassium ion from the exterior to the interior of the cell, it is required W=1.04.10^{-20}J of energy.

8 0
3 years ago
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