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Korolek [52]
3 years ago
8

Choose all the answers that apply. Nitrogen has an atomic number of 7. Its atomic mass is 14. Nitrogen has _____. seven electron

s seven neutrons seven electron shells 23 neutrons 14 electrons
Chemistry
2 answers:
yulyashka [42]3 years ago
5 0

Answer:

Nitrogen has 7 electrons as well as 7 neutrons. the atomic number represents the number of electrons in an atom

mixer [17]3 years ago
5 0

Answer:

Seven electrons, seven neutrons

Explanation:

Nitrogen

Atomic number(number of protons): 7

Atomic mass(number of protons and neutrons): 14

Since there are 7 protons and the atomic mass is 14, there are 7 neutrons as well that comprise the atomic mass.

From the information above, we can infer that:

There are seven electrons and

seven neutrons

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The bond between which two atoms is most
MariettaO [177]
The answer would be option 4
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3 years ago
What are m and n in the rate law equation? Rate = k[A]^m[B]^n A. They are the coefficients obtained from the equation. B. They a
Sav [38]
The answer is A. The m and n are the coefficients obtained from the equation. And important thing is that the equation need to be balanced before using its coefficients.
5 0
3 years ago
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Given the unbalanced equation below, answer the following: Calculate the number of liters of 3.00 M lead (II) iodide solution pr
mr_godi [17]

The number of liters of 3.00 M lead (II) iodide : 0.277 L

<h3>Further explanation</h3>

Reaction(balanced)

Pb(NO₃)₂(aq) + 2KI(aq) → 2KNO₃(aq) + PbI₂(s)

moles of KI = 1.66

From the equation, mol ratio of KI : PbI₂ = 2 : 1, so mol PbI₂ :

\tt \dfrac{1}{2}\times 1.66=0.83

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

\large \boxed {\bold {M ~ = ~ \dfrac {n} {V}}}

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

So the number of liters(V) of 3.00 M lead (II) iodide-PbI₂ (n=0.83, M=3):

\tt V=\dfrac{n}{M}\\\\V=\dfrac{0.83}{3}\\\\V=0.277~L

5 0
3 years ago
IF 14.07*10^26 molecules of magnesium chloride was produced in the following reaction, how many grams of magnesium reacted?
Wittaler [7]

Answer:

56160grams

Explanation:

First, we need to convert the number of molecules of magnesium chloride (MgCl2) into moles by dividing by Avagadro's number (6.02 × 10^23 molecules)

n = nA ÷ 6.02 × 10^23

n = 14.07 × 10^26 ÷ 6.02 × 10^23

n = 14.07/6.02 × 10^(26-23)

n = 2.34 × 10^3 moles of MgCl2

The balanced reaction given in the question is as follows:

Mg + 2HCl → MgCl2 + H2

If 1 mole of Mg produced 1 mole of MgCl2

Then, 2.34 × 10^3 moles of Mg will also produce 2.34 × 10^3 moles of MgCl2.

Using mole = mass ÷ molar mass (MM)

Molar mass of Mg = 24g/mol

mass = mole × MM

mass = 2.34 × 10^3 × 24

mass = 56.16 × 10^3

mass = 56160grams.

6 0
3 years ago
2. How many chlorine atoms are in 4 moles of chlorine?
RUDIKE [14]

Answer:

4

Explanation:

4 0
3 years ago
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