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vesna_86 [32]
3 years ago
14

You have two sealed jars of water at the same temperature. in the first jar there is a large amount of water. in the second jar

there is a small amount of water. using 3 -4 sentences explain how the vapor pressure of water in the first jar compares with the vapor pressure of water in the second jar.
Chemistry
1 answer:
n200080 [17]3 years ago
4 0
The vapor pressure of the jar with a large amount of water and the jar with a small amount of water is the same. Vapor pressure is an intrinsic property. This means that this property is not dependent on the amount of the substance. Vapor pressure is dependent only on temperature and since the temperature is the same for both jars, their vapor pressures are also the same.
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what actually is left over of water once it self ionizes? Like what exactly are the hydrogen and hydroxide ions? Do they remain
GrogVix [38]
The formula for the self ionization of water is 2H₂O(l)⇄H₃O⁺(aq)+OH⁻(aq)

The hydronium (H₃O⁺) is usually just referred to as a hydrogen ion or a proton (H⁺) and hydroxide (OH⁻) doesn't have another name that I am aware of.  These ions do stay in solution.  However the concentrations are really small and the equilibrium constant (K(w)) is 1×10⁻¹⁴.

I hope this helps.  Let me know if anything is unclear.
5 0
3 years ago
True or False <br> Matter is the ability to do work or cause change.
wel

<u>False</u> is the correct answer.

8 0
3 years ago
Read 2 more answers
In the reaction, A → Products, the rate constant is 3.6 × 10−4 s−1. If the initial concentration of A is 0.548 M, what will be t
Arada [10]

Answer:

        \large\boxed{\large\boxed{0.529M}}

Explanation:

Since the <em>rate constant</em> has units of <em>s⁻¹</em>, you can tell that the order of the reaction is 1.

Hence, the rate law is:

       r=d[A]/dt=-k[A]

Solving that differential equation yields to the well known equation for the rates of a first order chemical reaction:

      [A]=[A]_0e^{-kt}

You know [A]₀, k, and t, thus you can calculate [A].

       [A]=0.548M\times e^{-3.6\cdot 10^{-4}/s\times99.2s}

       [A]=0.529M

7 0
3 years ago
Boron has an average mass of 10.81. One isotope of boron has a mass of 10.012938 and a relative abundance of 19.80 percent. The
Andrej [43]

The average mass of an atom is calculated with the formula:

average mass = abundance of isotope (1) × mass of isotope (1) + abundance of isotope (2) × mass of isotope (2) + ...  an so on

For the boron we have two isotopes, so the formula will become:

average mass of boron = abundance of isotope (1) × mass of isotope (1) + abundance of isotope (2) × mass of isotope (2)

We plug in the values:

10.81 = 0.1980 × 10.012938  + 0.8020 × mass of isotope (2)

10.81 = 1.98 + 0.8020 × mass of isotope (2)

10.81 - 1.98 = 0.8020 × mass of isotope (2)

8.83 = 0.8020 × mass of isotope (2)

mass of isotope (2) = 8.83 / 0.8020

mass of isotope (2) = 11.009975

mass of isotope (1) = 10.012938 (given by the question)

5 0
3 years ago
Why estuaries are an important habitat for many marine organisms in comparison to the open ocean?
Alexxandr [17]

Answer:

There are more nutrients available in estuaries. There are more nutrients available in estuaries.

Explanation:

5 0
2 years ago
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