Question

In one of your experiments, you will roll a marble down a ramp to provide an initial horizontal velocity. Suppose you start the marble at rest (vo = 0 m/s) and it travels a distance of, d, down the ramp. Use 1-D kinematics to predict the velocity of the ball (vf ) at the bottom of the ramp. Hint: the acceleration of the ball down the ramp is 9.81*sin(θ) m/s2 where θ is the angle of the ramp. Record you answer in variables (you will calculate the velocity with magnitudes when you perform the experiment).

Answer 1

Answer:

$V_f=\sqrt{2gdsin\theta }\ m/s$

Explanation:

Initial velocity ,Vo= 0 m/s

Distance = d

a = g sin θ m/s²

From law of motion

$V_f^2=V_o^2+2gd$

Given that initial velocity is zero.

Vo= 0 m/s

a = g sin θ m/s²

V²f = 2. g .sin θ. d

$V_f=\sqrt{2gdsin\theta }\ m/s$