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sweet [91]
2 years ago
8

Describe how radio waves are different from sound waves.

Physics
2 answers:
Lilit [14]2 years ago
7 0

Answer:

sound and radio waves are completely different phenomena.

Explanation:

sammy [17]2 years ago
6 0
Radio waves are electromagnetic waves so therefore they can travel long distances in a vacuum. Sound waves are mechanical waves so they can’t not travel in the absence of a medium.
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Determine the magnitude of the resultant force FR=F1+F2FR=F1+F2. Assume that F1F1F_1 = 235 lblb and F2F2F_2 = 350 lb
Svetlanka [38]

Answer:

<em>585lb</em>

Explanation:

Given the formula for calculating the magnitude of the resultant force as;

F_R = F_1 + F_2

<em>Given </em>

<em></em>F_1 = 235 lb \ and \ F_2 = 350 lb\\F_R = 235lb + 350lb\\F_R = 585lb\\<em></em>

<em>Hence the magnitude of the resultant force is 585lb</em>

4 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
mestny [16]
C standards are based on observable, reproducible natural phenomena.
3 0
3 years ago
____ enforced regulations primarily aim to reduce environmental pesticide contamination
Ket [755]

Environmental Protection Agency enforced regulations primarily aim to reduce environmental pesticide contamination.

<h3>What is a Pesticide?</h3>

This refers to a chemical which is used to control pests and examples include insecticide, nematicide etc.

Environmental Protection Agency is government owned and ensures strict enforcement of regulations to reduce environmental pesticide contamination which could lead to death of beneficial organisms.

Read more about Environmental Protection Agency here brainly.com/question/23486143

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8 0
1 year ago
A ball is dropped from rest from the top of a cliff that is 24 m high. From ground level, a second ball is thrown straight upwar
sesenic [268]

Answer:

6.0 m below the top of the cliff

Explanation:

We can find the velocity at which the ball dropped from the cliff reaches the ground by using the SUVAT equation

v^2-u^2 = 2gd

where

u = 0 (it starts from rest)

g = 9.8 m/s^2 (acceleration of gravity, we assume downward as positive direction)

h = 24 m is the distance covered

Solving for h,

v=\sqrt{2gh}=\sqrt{2(9.8)(24)}=21.7 m/s

So the ball thrown upward is launched with this initial velocity:

u = 21.7 m/s

From now on, we take instead upward as positive direction.

The vertical position of the ball dropped from the cliff at time t is

y_1 = h - \frac{1}{2}gt^2

While the vertical position of the ball thrown upward is

y_2 = ut - \frac{1}{2}gt^2

The two balls meet when

y_1 = y_2\\h-\frac{1}{2}gt^2 = ut - \frac{1}{2}gt^2 \\h = ut \rightarrow t = \frac{h}{u}=\frac{24}{21.7}=1.11 s

So the two balls meet after 1.11 s, when the position of the ball dropped from the cliff is

y_1 = h -\frac{1}{2}gt^2 = 24-\frac{1}{2}(9.8)(1.11)^2=18.0 m

So the distance below the top of the cliff is

d=24.0 - 18.0 = 6.0 m

4 0
3 years ago
The combined gas law does not account for changes in _____.
Elan Coil [88]

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8 0
3 years ago
Read 2 more answers
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