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Rzqust [24]
3 years ago
10

Let's just say I want to get my mixture to a certain pH but I add too much water to my solution. Can I just add the same volume

of my substance as the water I added back into the mixture to get my initial pH?why/why not?
Chemistry
1 answer:
Dafna11 [192]3 years ago
4 0

Answer:

You can

Explanation:

The concentration doesn't change when its equals out.

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What kind of energy can be mainly excited by us/visible light
erica [24]
I'm thinking the answer you are looking for is light energy. With the sunlight there is light energy and heat.

3 0
3 years ago
0.75 mol hydrogen sulfide (H2S)
Bumek [7]

Answer:

• Information and media literacy

Directions

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Directions

Read the instructions for this self-checked activity. Type in your response to each question, and check your answers. At the end of the activity, write

brief evaluation of your work.

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4 0
2 years ago
Read 2 more answers
For the following example, list the given and unknown information (including gratis or moles)
Setler79 [48]

Answer:

9.6 moles O2

Explanation:

I'll assume it is 345 grams, not gratis, of water.  Hydrogen's molar mass is 1.01, not 101.

The molar mass of water is 18.0 grams/mole.

Therefore:  (345g)/(18.0 g/mole) = 19.17 or 19.2 moles water (3 sig figs).

The balanced equation states that:  2H20 ⇒ 2H2 +02

It promises that we'll get 1 mole of oxygen for every 2 moles of H2O, a molar ratio of 1/2.

get (1 mole O2/2 moles H2O)*(19.2 moles H2O) or 9.6 moles O2

6 0
2 years ago
Which metalloid is often found in microchips, semiconductors, and sand?a. boron b. arsenic c. germanium d. silicon​
elena-14-01-66 [18.8K]

Answer:

silicon

Explanation:

Silicon. Silicon is often found in electronic devices, as well as the sand.

hope this helps UwU

5 0
3 years ago
Read 2 more answers
A mineral consisted of 29.4% calcium, 23.5% sulfur and 47.1% oxygen. What is the empirical formula?
inessss [21]
Step  one  calculate  the  moles  of  each  element
that  is  moles= %  composition/molar  mass
molar  mass  of    Ca  =  40g/mol,     S=  32  g/mol ,   O=  16 g/mol

moles  of      Ca = 29.4 /40g/mol=0.735 moles,      S= 23.5/32  =0.734 moles,  O= 47.1/16= 2.94   moles

calculate  the mole  ratio  by  dividing   each  mole with  smallest  mole   that   is  0.734
Ca=  0.735/0.734= 1,      S=  0.734/0.734 =1,   O  = 2.94/  0.734= 4
therefore  the  emipical  formula  =  CaSO4
5 0
3 years ago
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