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Flura [38]
3 years ago
5

8. Two forces of 10 N and 30 N are applied to a 10 kg box. Find (1) the box’s acceleration when both forces point due east and (

2) the box’s acceleration when 10 N force points due east and 30 N force points due west.
Physics
1 answer:
love history [14]3 years ago
3 0

(1) acceleration, a = 4 m/s^{2}  (2) acceleration of 10 N, a_{1} = 1 m/s^{2} and acceleration of 30 N, a_{2} = 3 m/s^{2}

Explanation:

  • Here, the acceleration of the object could be found using the equation derived in the second law of motion. The equation is given as, F = ma where m is the acceleration of the object, m is the mass of the object and F is the applied on the object.
  • Let a_{1} be the acceleration for force 10 N, to find acceleration rearrange the equation to a = \frac{F}{m}. When we substitute 10 N force and 10 kg mass of the box in the equation. We will get a_{1} = 1 m/s^{2}
  • Let a_{2}  be the acceleration for force 30 N, to find acceleration rearrange the equation to F = \frac{F}{m}. When we substitute 30 N force and 10 kg mass of the box in the equation. We will get a_{2} = 3 m/s^{2}
  • To find the combined, just add the force and substitute in the above equation. Hence, a = 4 m/s^{2}
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Kryger [21]

Answer:

The right solution will be the "2v".

Explanation:

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⇒  \omega=\frac{v_{translational}}{r}

Significant meaning is obtained, as speeds are in the same direction. Therefore the speed of rotation becomes supplied by:

⇒  v_{rotational}=\omega \times r

On substituting the estimated values, we get

⇒                   =\frac{v_{translational}}{r} \times r

⇒                   =v_{translational}

So that the velocity will be:

⇒  v_{rolling}=v+v

⇒              =2v

4 0
3 years ago
(1) Assume that the lights in your kitchen use 300 watts. How much energy (in kWh) does it use and how much does it cost to leav
lbvjy [14]

Answer:

the cost to leave the lights on 24 hours a day for one year is 31,536 cents or 315.36 dollars

Explanation:

Given that;

P = 300 watts = 300/1000 = 0.3

t = 24hrs a day

In a calendar year, we have 365 days

so;

E = 0.3 × 365 × 24

E = 2628 KWh

given that;  1 KWh = 12 cent

then 2628  KWh is x

x = 2628 × 12

x = 31,536 cents or 315.36 dollars

Therefore, the cost to leave the lights on 24 hours a day for one year is 31,536 cents or 315.36 dollars

7 0
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Problema 1
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A person in a boat sees a fish in the water (n = 1.33, the light rays making an angle of 40? relative to the water's surface. wh
jek_recluse [69]
We know that the measure of an incident ray is:  α 1 = 40°.
The index of refraction:
- for the air : n 1 = 1.00,
- for the water: n 2 = 1.33
Snell`s Law of Refraction :
n 1 · sin α 1 = n 2 · sin α 2
sin α 2 = n 1 · sin α 1 / n 2 =
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α 2 = sin ^(-1) 0.4833
α 2 = 28.9 °
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4 0
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