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suter [353]
3 years ago
6

Research three different types of fire extinguisher and explain how these can be used to put out different fires, you must relat

e this to the fire triangle and the section that is removed
Chemistry
1 answer:
Vilka [71]3 years ago
7 0
The fire triangle is composed of 
1) heat
2) fuel
3) oxidizing agent (oxygen)

Types of fire extinguishers:
1) Water and Foam - <span> extinguish the fire by taking away the </span>heat<span> element of the fire triangle. Foam agents separate the </span>oxygen<span> element from the other elements.</span>
2) Carbon dioxide - <span>extinguish fire by taking away the </span>oxygen<span> element of the fire triangle and also be removing the </span>heat<span> with a very cold discharge.</span>
3) Dry Chemical - <span>extinguish the fire primarily by interrupting the </span>chemical reaction<span> of the fire triangle.</span>
4) Wet Chemical - <span>extinguishes the fire by removing the heat of the fire triangle and prevents re-ignition by creating a barrier between the </span>oxygen<span> and </span>fuel<span> elements</span>
5) Clean Agent - <span>extinguish the fire by interrupting the </span>chemical reaction<span> of the fire triangle</span>
6) Dry Powder - extinguish the fire by separating thefuel<span> from the </span>oxygen<span> element or by removing the </span>heat<span> element of the fire triangle</span>
7) Water Mist - <span>extinguish the fire by taking away the </span>heatelement of the fire triangle
8) Cartridge Operated Dry Chemical - extinguish the fire primarily by interrupting the chemical reaction<span> of the fire triangle</span>

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A 1.00 g sample of octane (C8H18) is burned in a bomb calorimeter with a heat capacity of 837J∘C that holds 1200. g of water at
lubasha [3.4K]

Answer:

The heat of combustion for 1.00 mol of octane is  -5485.7 kJ/mol

Explanation:

<u>Step 1:</u> Data given

Mass of octane = 1.00 grams

Heat capacity of calorimeter = 837 J/°C

Mass of water = 1200 grams

Temperature of water = 25.0°C

Final temperature : 33.2 °C

<u> Step 2:</u> Calculate heat absorbed by the calorimeter

q = c*ΔT

⇒ with c = the heat capacity of the calorimeter = 837 J/°C

⇒ with ΔT = The change of temperature = T2 - T1 = 33.2 - 25.0 : 8.2 °C

q = 837 * 8.2 = 6863.4 J

<u>Step 3:</u> Calculate heat absorbed by the water

q = m*c*ΔT

⇒ m = the mass of the water = 1200 grams

⇒ c = the specific heat of water = 4.184 J/g°C

⇒ ΔT = The change in temperature = T2 - T1 = 33.2 - 25  = 8.2 °C

q = 1200 * 4.184 * 8.2 =  41170.56 J

<u>Step 4</u>: Calculate the total heat

qcalorimeter + qwater = 6863.4 + 41170. 56 = 48033.96 J  = 48 kJ

Since this is an exothermic reaction, there is heat released. q is positive but ΔH is negative.

<u>Step 5</u>: Calculate moles of octane

Moles octane = 1.00 gram / 114.23 g/mol

Moles octane = 0.00875 moles

<u>Step 6:</u> Calculate heat combustion for 1.00 mol of octane

ΔH = -48 kJ / 0.00875 moles

ΔH = -5485.7 kJ/mol

The heat of combustion for 1.00 mol of octane is  -5485.7 kJ/mol

8 0
3 years ago
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