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Rama09 [41]
3 years ago
8

Deuterium is an isotope of hydrogen. It has a mass number of two. Which describes a deuterium atom? A. a nucleus of one proton a

nd one neutron, which is orbited by one electron B. a nucleus of one proton, which is orbited by one neutron and one electron C. a nucleus of one neutron, which is orbited by one electron D. a nucleus of two neutrons which is orbited by two electrons
Chemistry
2 answers:
Stells [14]3 years ago
6 0

also known as heavy hydrogen) is one of two stable isotopes of hydrogen (the other being protium, or hydrogen-1). The nucleus of deuterium, called a deuteron, contains one proton and one neutron, whereas the far more common protium has no neutron in the nucleus.

arsen [322]3 years ago
4 0

Answer:

A. a nucleus of one proton and one neutron, which is orbited by one electron.

Explanation:

Isotopes have the same atomic number and different mass number. The atomic number is the numbers of protons in the nucleus and defines each element while the mass number is the sum of protons and neutrons in the nucleus.

An hydrogen atom with a mass number of two means that its nucleus has one proton and one neutron because the atomic number of hydrogen is 1, otherwise it wouldn’t be hydrogen, so it has 1 proton and to complete the mass number of two it must have 1 neutron.

On the other hand, the atomic model says that the nucleus is orbited by electrons. The number of electrons orbiting the nucleus is given by the atomic number. Then an atomic number of 1 means that 1 electron orbits the nucleus with one proton.

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Match the following terms with their definitions:
stepan [7]
Hi,

Homogeneous mixture 2
Heterogeneous 3
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Solution 5
Compound 4
6 0
3 years ago
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Determine the empirical formula. a 3.880g sample contains 0.691g of magnesium , 1.84 g of sulfur , and 1.365 g of oxygen .
Aliun [14]

Answer:

Mg S2 O3

Explanation:

.691 g of Mg  is .284 mole

1.84 g of S    is .5739 mole

1.365 g of O is  .8531 mole      you can see the ratio is ~  1 :2 :3

                                                        Mg S2 O3

4 0
2 years ago
On the reaction below, label the BSA, BSB, CA, and CB. CH3COOH + H2O → CH3COO– + H3O+
Ostrovityanka [42]

Answer:

Acid(BSA) = CH₃COOH

Base (BSB) = H₂O

Conjugate base (CB) = CH₃COO⁻

Conjugate acid (CA) = H₃O⁺

Explanation:

Equation of reaction;

CH₃COOH + H₂O → CH₃COO⁻ + H₃O⁺

Hello,

From my understanding of the question, we are required to identify the

1) Acid

2) Base

3) conjugate acid

4) conjugate base in the reaction

Acid (BSA) = CH₃COOH

Base (BSB) = H₂O

CA = conjugate acid = H₃O⁺

CB = conjugate base = CH₃COO⁻

7 0
2 years ago
has a standard free‑energy change of − 3.59 kJ / mol at 25 °C. What are the concentrations of A , B , and C at equilibrium if, a
Mamont248 [21]

Answer: The concentrations of A , B , and C at equilibrium are 0.1583 M, 0.2583 M, and 0.1417 M.

Explanation:

The reaction equation is as follows.

               A + B \rightarrow C

Initial :     0.3   0.4          0

Change:  -x       -x           x

Equilbm: (0.3 - x)  (0.4 - x)  x  

We know that, relation between standard free energy and equilibrium constant is as follows.

      \Delta G = -RT ln K

Putting the given values into the above formula as follows.

      \Delta G = -RT ln K

      -3.59 kJ/mol = -8.314 \times 10^{-3} kJ/mol K ln (\frac{x}{(0.3 - x)(0.4 - x)})

                x = 0.1417

Hence, at equilibrium

  •  [A] = 0.3 - 0.1417

       = 0.1583 M

  •  [B] = 0.4 - 0.1417

       = 0.2583 M

  •  [C] = 0.1417 M
5 0
2 years ago
Can Air can be warmed or cooled by the surface below
suter [353]
I believe it can be warm because usually the surface below us is warm itself, causing the air to be warm as well. The temperature can vary as well
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3 years ago
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