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wlad13 [49]
2 years ago
5

Part B Redox titrations are used to determine the amounts of oxidizing and reducing agents in solution. For example, a solution

of hydrogen peroxide, H2O2, can be titrated against a solution of potassium permanganate, KMnO4. The following equation represents the reaction: 2KMnO4(aq)+H2O2(aq)+3H2SO4(aq)→3O2(g)+2MnSO4(aq)+K2SO4(aq)+4H2O(l) A certain amount of hydrogen peroxide was dissolved in 100. mL of water and then titrated with 1.68 M KMnO4. What mass of H2O2 was dissolved if the titration required 17.8 mL of the KMnO4 solution? Express your answer with the appropriate units. View Available Hint(s) mass of H2O2H 2 O 2 = Previous Answers Incorrect; Try Again; 5 attempts remaining Provide Feedback Incorrect. Incorrect; Try Again; 5 attempts remaining. No additional feedback.
Chemistry
1 answer:
MissTica2 years ago
5 0

Answer:

0,508g of H₂O₂

Explanation:

For the reaction:

2KMnO₄(aq) + H₂O₂(aq) + 3H₂SO₄(aq) → 3O₂(g) + 2MnSO₄(aq) + K₂SO₄(aq) + 4H₂O(l)

2 moles of KMnO₄ react with 1 mol of H₂O₂.

In the titration, moles of KMnO₄ required were:

1,68M×0,0178L = 0,0299 moles of KMnO₄. Moles of H₂O₂ are:

0,0299 moles of KMnO₄×\frac{1molH_{2}O_{2}}{2molKMnO_{4}} = 0,01495 moles of H₂O₂. As molar mass of H₂O₂ is 34,01g/mol, mass of H₂O₂ was dissolved is:

0,01495 moles of H₂O₂×\frac{34,01g}{1molH_{2}O_{2}} = <em>0,508g of H₂O₂</em>

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Luba_88 [7]

Answer:

its -000.5

Explanation:

6 0
3 years ago
What is the volume of 2.1 moles of chlorine gas (Cl2) at standard temperature and pressure (STP)?
uysha [10]
Given:
<span> 2.1 moles of chlorine gas (Cl2) at standard temperature and pressure (STP)
Required:
volume of CL2
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Use the ideal gas law
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V = nRT/P
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5 0
3 years ago
Combustion analysis of 0.300 g of an unknown compound containing carbon, hydrogen, and oxygen produced 0.5213 g of co2 and 0.283
Lyrx [107]
First, we have to get how many grams of C & H & O in the compound:
- the mass of C on CO2 = mass of CO2*molar mass of C /molar mass of CO2
                                        = 0.5213 * 12 / 44 = 0.142 g
- the mass of H atom on H2O = mass of H2O*molar mass of H / molar mass of H2O
                                                 =0.2835 * 2 / 18 = 0.0315 g
- the mass of O = the total mass - the mass of C atom - the mass of H atom
                          =  0.3 - 0.142 - 0.0315 = 0.1265 g
Convert the mass to mole by divided by molar mass
C(0.142/12) H(0.0315/2) O(0.1265/16) 
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6 0
3 years ago
What<br>your events made Gautam Buddha to<br>go in search of the truth?​
Dafna11 [192]

Answer:

The Buddha (also known as Siddhartha Gotama or Siddhārtha Gautama[note 3] or Buddha Shakyamuni) was a philosopher, mendicant, meditator, spiritual teacher, and religious leader who lived in Ancient India (c. 5th to 4th century BCE).[5][6][7][note 4] He is revered as the founder of the world religion of Buddhism, and worshipped by most Buddhist schools as the Enlightened One who has transcended Karma and escaped the cycle of birth and rebirth.[8][9][10] He taught for around 45 years and built a large following, both monastic and lay.[11] His teaching is based on his insight into duḥkha (typically translated as "suffering") and the end of dukkha – the state called Nibbāna or Nirvana.

The Buddha was born into an aristocratic family in the Shakya clan but eventually renounced lay life. According to Buddhist tradition, after several years of mendicancy, meditation, and asceticism, he awakened to understand the mechanism which keeps people trapped in the cycle of rebirth. The Buddha then traveled throughout the Ganges plain teaching and building a religious community. The Buddha taught a middle way between sensual indulgence and the severe asceticism found in the Indian śramaṇa movement.[12] He taught a spiritual path that included ethical training and meditative practices such as jhana and mindfulness. The Buddha also critiqued the practices of Brahmin priests, such as animal sacrifice.

A couple of centuries after his death he came to be known by the title Buddha, which means "Awakened One" or "Enlightened One".[13] Gautama's teachings were compiled by the Buddhist community in the Suttas, which contain his discourses, and the Vinaya, his codes for monastic practice. These were passed down in Middle-Indo Aryan dialects through an oral tradition.[14][15] Later generations composed additional texts, such as systematic treatises known as Abhidharma, biographies of the Buddha, collections of stories about the Buddha's past lives known as Jataka tales, and additional discourses, i.e, the Mahayana sutras.

Explanation:

8 0
3 years ago
A student heats 10.52 g of sodium hydrogen carbonate in a crucible until the compound completely decomposes to sodium carbonate
saveliy_v [14]

Answer:

m_{Na_2CO_3}^{theoretical}=6.636gNa_2CO_3

Explanation:

Hello!

In this case, since the decomposition of sodium hydrogen carbonate is:

2NaHCO_3(s)\rightarrow Na_2CO_3(s)+H_2O(g)+CO_2(g)

Thus, since there is a 2:1 mole ratio between the sodium hydrogen carbonate and sodium carbonate, and the molar masses are 84.01 and 105.99 g/mol respectively, we obtain the following theoretical yield:

m_{Na_2CO_3}^{theoretical}=10.52gNaHCO_3*\frac{1molNaHCO_3}{84.01gNaHCO_3}*\frac{1molNa_2CO_3}{2molNaHCO_3}  *\frac{105.99gNa_2CO_3}{1molNa_2CO_3}\\\\ m_{Na_2CO_3}^{theoretical}=6.636gNa_2CO_3

Best regards!

4 0
2 years ago
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