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3 years ago

How do I figure the electronegativity difference of sugar C^12H^22O^11?

1 answer:

6 0

Well, a molecule of this carbohydrate would essentially have no electronegativity difference as it is a Nonpolar compound, and not that of a polar one. All electrons between the atoms would ultimately have a net dipole value of 0, indicating that the molecule is Nonpolar. Thus does not have a partial positive and or a partial negative charge.

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What contribution did Robert Boyle make towards the field of chemistry

GREYUIT [131]

Answer:

Boyle's law, which describes the inversely proportional relationship between the absolute pressure and volume of a gas, if the temperature is kept constant within a closed system. Among his works, The Sceptical Chymist is seen as a cornerstone book in the field of chemistry.

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3 years ago

Give two reasons why quarrying is bad for the environment?

Oksi-84 [34.3K]

1) The longer the quarrying goes on the less and less recources we will have, soon leading to no more recources

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3 years ago

When a gas in a cylinder is compressed at constant temperature by a piston, the pressure of the gas increases. Consider the foll

Marizza181 [45]

Answer:

Answer below!!

Explanation:

The volume of a gas is inversely proportional to presure keeping the temperature the same.

Hope I helped!!!

4 0

2 years ago

Chloroform is an excellent solvent for extracting caffeine from water. The distribution coefficient, KD, (Cchloroform/Cwater) fo

Art [367]

The relative volumes of chloroform and water that should be used is 9:10

Concentration of solution in chloroform = $90$ ( moles of chloroform )

Concentration of solution in water = $10$ ( moles of water )

Dissociation constant at $25^oC$ ; $K_D = 10$

$K_D =$ Concentration of solution in chloroform / Concentration of solution in water

Meaning;

$K_D = \frac{\frac{mole\ of\ chloroform}{volume\ of\ chloroform} }{\frac{mole\ of\ water}{volume\ of\ water} }$

Since $90$ mole is present in chloroform and $10$ mole is present in water, Total mole of Caffeine present is $100$

Now, we substitute our given values into the equation

$10 = \frac{\frac{90}{volume\ of\ chloroform} }{\frac{10}{volume\ of\ water} }\\\\10 *\frac{10}{volume\ of\ water} = \frac{90}{volume\ of\ chloroform} \\\\\frac{100}{volume\ of\ water} = \frac{90}{volume\ of\ chloroform}\\\\\frac{volume\ of\ chloroform}{volume\ of\ water} = \frac{90}{100}\\\\ \frac{volume\ of\ chloroform}{volume\ of\ water} = \frac{9}{10}\\\\ \frac{volume\ of\ chloroform}{volume\ of\ water} = 9:10$

Therefore, the relative volumes of chloroform and water that should be used is 9:10

Learn more; brainly.com/question/11060225

8 0

2 years ago

Question 3 (5 points)

Daniel [21]

Answer:

332.918g O2

Explanation:

I'm having some issues with the work however, your final answer should be 332.918g O2

Hope this helped!

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2 years ago