Answer: a) W(earth) = 935.62 lbs
b) Mass of rocks in slugs = 29.06 slugs
Explanation:
a) From Newton's law, W = mg. Whether on the moon or on earth. Although, the mass of the rocks everywhere is the same, that is, mass of rocks on the moon = mass of rocks on earth.
W(moon) = mg(moon)
W(moon) = 154 lbs
g(moon) = 5.30 ft/s2
m = W(moon)/g(moon) = 154/5.3 = 29.06 lb.s2/ft
W(earth) = m g(earth)
g(earth) = 32.2 ft/s2
W(earth) = 29.06 × 32.2 = 935.62 lbs.
b) A slug = 1 lb.s2/ft, therefore the mass of the rocks in slugs is 29.06 slugs.
QED!
Answer:
See the detailed answer in attached file.
Explanation :
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Answer:
The correct answer is option (c) An experimental observation that the velocity of a fluid in contact with a solid surface is equal to the velocity of the surface.
Explanation
Solution:
When a fluid is in proximity to the boundary the solid and the velocities are the same or uniform for the fluid and the surface, no slip condition does not exist.
However, because the no-slip meets the expectations for gas and liquids, this condition no way connected in this case of two solid in proximity.
hence, the other options are wrong here.
Answer:
<em>Heat rejected to cold body = 3.81 kJ</em>
Explanation:
Temperature of hot thermal reservoir Th = 1600 K
Temperature of cold thermal reservoir Tc = 400 K
<em>efficiency of the Carnot's engine = 1 - </em>
<em> </em>
eff. of the Carnot's engine = 1 - 
eff = 1 - 0.25 = 0.75
<em>efficiency of the heat engine = 70% of 0.75 = 0.525</em>
work done by heat engine = 2 kJ
<em>eff. of heat engine is gotten as = W/Q</em>
where W = work done by heat engine
Q = heat rejected by heat engine to lower temperature reservoir
from the equation, we can derive that
heat rejected Q = W/eff = 2/0.525 = <em>3.81 kJ</em>
