Answer:
The smallest wire diameter that can be used is 1 cm
Explanation:
First, we find the smallest diameter using the criterion of maximum normal stress:
Max. Stress = 150 x 10^6 Pa = F/A
150 x 10^6 Pa = 12000 N/(πd²/4)
d² = (12000 N)(4)/(150 x 10^6 Pa)(π)
d = √1.0185 x 10^-4 m²
d = 0.010 m = 1 cm
Now, we find the smallest diameter using the criterion of maximum strain:
Max. Strain = Max. Change in Length/Original Length = 0.025 m/50 m
Max. Strain = 5 x 10^-4 mm/mm
Now,
Max. Strain = Stress/E = (F/A)/E = F/AE
using values:
5 x 10^-4 mm/mm = (12000 N)/(200 x 10^9 Pa)(πd²/4)
d =√(12000 N)(4)/(5 x 0^-4)(200 x 10^9 Pa)(π)
d = 0.012 m = 1.2 cm
Now, by comparison in both cases it can be noted that the smallest value of the diameter is <u>1 cm</u>, which is limited by maximum stress.
Answer:
Glass
Explanation:
Please mark me the brilliant
I think it’s B.) it’s signed by the customer
Answer:
A. Forces that act perpendicular to the surface and pull an object apart exert a tensile stress on the object.
Explanation:
Tensile stress is referred as a deforming force, in which force acts perpendicular to the surface and pull an object apart, attempting to elongate it.
The tensile stress is a type of normal stress, in which a perpendicular force creates the stress to an object’s surface.
Hence, the correct option is "A."
Answer:
The power of force F is 115.2 W
Explanation:
Use following formula
Power = F x V
= F cos0
= (30) x 4/5
= 24N
Now Calculate V using following formula
V = 
+ at
= 0
a = / m
a = 24N / 20 kg
a = 1.2m / 
no place value in the formula of V
V = 0 + (1.2)(4)
V = 4.8 m/s
So,
Power = x V
Power = 24 x 4.8
Power = 115.2 W
