By what i know i think that the answer would be A a homogeneous mixture.
Since both hv same mass and elsstic collision, so their velocity will exchange. Bob A will stop and bob B will move with speed of A just before the collision.
Speed will be = squreroot ( 2*g*L)
L is length of pendulum
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Assume the snow is uniform, and horizontal.
Given:
coefficient of kinetic friction = 0.10 = muK
weight of sled = 48 N
weight of rider = 660 N
normal force on of sled with rider = 48+660 N = 708 N = N
Force required to maintain a uniform speed
= coefficient of kinetic friction * normal force
= muK * N
= 0.10 * 708 N
=70.8 N
Note: it takes more than 70.8 N to start the sled in motion, because static friction is in general greater than kinetic friction.
Answer:
Explanation:
From the question we are told that:
Mass 
Charge 
Velocity 
Length of Wire 
Current 
Generally the equation for Magnetic Field of Wire B is mathematically given by
Generally the equation for Force on the plane F is mathematically given by
Therefore
Therefore in Terms of g's
