Answer:
2.05 kgm²/s
Explanation:
I = moment of inertia of cylinder = 0.016 kgm²
r = radius of the cylinder = 6 cm = 0.06 m
v = linear speed of the cylinder = 7.7 m/s
w = angular speed of cylinder
Using the equation
v = r w
7.7 = (0.06) w
w = 128.33 rad/s
Magnitude of angular momentum of the cylinder is given as
L = I w
L = (0.016) (128.33)
L = 2.05 kgm²/s
Answer:
α=9.42 rad/s T= 0.014 rad/s
Explanation:
Low speed= Wi=3 rps = 3*2*π rad/s= 6π rad/sec
Medium speed= Wf= 9 rps= 9*2*π rad/sec= 18 rad/sec
time= t= 4 sec
Angular acceleration=α=
⇒α=(18 π - 6 π)/4
⇒α=9.42 rad/s
b).
Rotational inertia= I = 1.5*10^-3 kg-m^2
Net torque= T = I*α = (1.5*10^-3) * (9.42) rad/s^2
⇒T= 0.014 rad/s^2
Answer:
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