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Goshia [24]
3 years ago
10

Technician A says that a tire will increase or decrease approximately 1 psi for each 10°F change of temperature. Technician B sa

ys that if the vehicle has been driven to warm the tires, you must adjust the air pressure down to the manufacturer's recommended pressure. Who is correct?
A. Tech A
B. Tech B
C. Both Techs A and B
D. Neither Tech A nor B
Physics
1 answer:
bearhunter [10]3 years ago
8 0

Answer:

Technician A

Explanation:

It is seen that a tire pressure will increase or decrease 1 psi for each 10^{\circ} F  change in temperature.

For Technician B vehicle pressure should not be adjusted after tire has been warmed as the warm air may increase the pressure but it will be auto adjusted as  the temperature falls to normal .          

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we know that,

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A boy walks a distance of 100 meters to the right at a steady speed of 1.00 m/s. Then he stops for 30 seconds. Then returns back
Mamont248 [21]

Explanation:

speed=\frac{Distance}{time}

In the figure attached:

A boy travels AB distance of 100 m, with speed of 1.00 m/s

AB = 100 m

1.00 m/s=\frac{100 m}{t_1}

t_1=100 s

After reaching at point B he stops there at for 30 seconds.

t_2= 30 s

After , 30 seconds he he comes back to his initial position that is A with steady speed of 1.00 m/s.

Distance covered from B to A= 100 m

Time taken by him during coming back=t_3

1.00=\frac{100 m}{t_3}

t_3=100 s

After returning to to point A he turns left and moves towards point C with speed of 1.5 m/s for 2 minutes.

Distance of AC = ?

t_4=2 min= 120 s

1.5 m/s=\frac{AC}{120 s}

AC = 180 m

The total time of his round trip is:T

T=t_1+t_2+t_3+t_4=100 s+30 s(stop)+ 100 s(returning)+120 s=350 s

The total distance: D

D = AB + BA (returning) + AC=100 m + 100 m + 180 m = 380 m[/tex]

The total displacement of boy:

Displacement is the shortest distance between the initial point and final point.

He first walked to point B from A and then came back to A . And after that walking to point C from A.So, the final displacement (d) is from A to C.

d = AC = 180 m

The total displacement of boy is 180 m.

The average speed of the boy is given by:

=\frac{AB+BA+AC}{t_1+t_2+t_3+t_4}=\frac{D}{T}

\frac{D}{T}=\frac{380 m}{350 s}=1.085 m/s

The average velocity of the boy is given by:

=\frac{AC}{t_1+t_2+t_3+t_4}=\frac{d}{T}

\frac{d}{T}=\frac{180 m}{350 s}=0.5142 m/s

5 0
4 years ago
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