Answer:
The turnover number of the enzyme molecule bovine carbonic anhydrase = 67,272,727.27 s^–1.
Explanation:
Given:
The concentration of bovine carbonic anhydrase = total enzyme concentration = Et = 3.3 pmol⋅L^–1 = 3.3 × 10^–12 mol.L^–1
The maximum rate of reaction = Rmax (Vmax) = 222 μmol⋅L^–1⋅s^–1 = 222 × 10^–6 mol.L^–1⋅s^–1
The formula for the turnover number of an enzyme (kcat, or catalytic rate constant) = Rmax ÷ Et = 222 × 10^–6 mol.L^–1⋅s^–1 ÷ 3.3 × 10^–12 mol.L^–1 = 67,272,727.27 s^–1
Therefore, the turnover number of the enzyme molecule bovine carbonic anhydrase = 67,272,727.27 s^–1
Assuming that the table has 4 legs. the upward force is equal to the downwardd force. the downward force of the table is the weight of the table. so the upward force is also the weight of the table but in opposite direction, so the upward force in on one leg is 1/4 of the weight of the table
It is biotic and nest are strong
Answer:
in a transverse wave, The directions that energy and matter travel in are perpendicular to one another.
these waves are types of mechanical waves that doesn't require any material medium to transfer.
