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Alexeev081 [22]
3 years ago
11

. Determinar la magnitud de la fuerza que recibe un cuerpo de 45 kg, la cual le produce una aceleración cuya magnitud es de 5 m/

s2.
Physics
1 answer:
PSYCHO15rus [73]3 years ago
6 0

Answer:

225 N

Explanation:

Según la segunda ley de Newton;

F = ma

F = fuerza

m = masa

a = aceleración

Por eso;

F = 45 kg * 5 m / s ^ 2

F = 225 N

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calculate the electric field strength between two parallel plates separated by 0.50 cm, across which is a potential of 12 volts.
Alexxandr [17]
Formula for Electric Field strength , E =  V/d

where V = Voltage in volts, and d = distance of separation in meters.

d = 0.5 cm = 0.005 m,    V = 12 V

E = V/d =  12 / 0.005

E = 2400

Electric Field Strength = 2400 Volts/meter 
3 0
3 years ago
Can you help me please?
egoroff_w [7]
<h3>Answer</h3>

option B)

19N

<h3>Explanation</h3>

If the object is at equilibrium, then the net force acting upon the object should be 0 N. Thus, if all the forces are added together, horizontal and vertical forces separately, then the resultant force (the vector sum) should be 0 Newton.

As we only need to find the magnitude of x-component of force F

so find all x component/horizontal forces acting on the object.

50cos(40) - 40cos(25) + 30cos(55) + x = 0

38.30 - 36.25 + 17.21 + x + = 0

19.26 + x = 0

x = - 19.26

x ≈ 19 (magnitude only)

7 0
3 years ago
How do particles move when a transverse wave passes through a medium?
bagirrra123 [75]
<span> In </span>transverse waves<span>, </span>particles<span> of the</span>medium<span> vibrate </span>to<span> and from in a direction perpendicular </span>to<span> the direction of energy transport. </span>
4 0
3 years ago
The downlink frequency is lower than the uplink frequency. True or False
miv72 [106K]

Answer:

I think it is true

Explanation:

4 0
3 years ago
Read 2 more answers
A child is holding a wagon from rolling straight back down in a driveway that inclined at 20 degree horizontal. if the wagon wei
Alenkinab [10]

Answer:

F = 51.3°

Explanation:

The component of weight parallel to the inclined plane must be responsible for the rolling back motion of the car. Hence, the force required to be applied by the child must also be equal to that component of weight:

F = Parallel\ Component\ of\ Weight\ of\ Wagon= WSin\theta\\

where,

W = Weight of Wagon = 150 N

θ = Angle of Inclinition = 20°

Therefore,

F = (150\ N)Sin\ 20^o

<u>F = 51.3°</u>

8 0
2 years ago
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