Formula for Electric Field strength , E = V/d
where V = Voltage in volts, and d = distance of separation in meters.
d = 0.5 cm = 0.005 m, V = 12 V
E = V/d = 12 / 0.005
E = 2400
Electric Field Strength = 2400 Volts/meter
<h3>Answer</h3>
option B)
19N
<h3>Explanation</h3>
If the object is at equilibrium, then the net force acting upon the object should be 0 N. Thus, if all the forces are added together, horizontal and vertical forces separately, then the resultant force (the vector sum) should be 0 Newton.
As we only need to find the magnitude of x-component of force F
so find all x component/horizontal forces acting on the object.
50cos(40) - 40cos(25) + 30cos(55) + x = 0
38.30 - 36.25 + 17.21 + x + = 0
19.26 + x = 0
x = - 19.26
x ≈ 19 (magnitude only)
<span> In </span>transverse waves<span>, </span>particles<span> of the</span>medium<span> vibrate </span>to<span> and from in a direction perpendicular </span>to<span> the direction of energy transport. </span>
Answer:
F = 51.3°
Explanation:
The component of weight parallel to the inclined plane must be responsible for the rolling back motion of the car. Hence, the force required to be applied by the child must also be equal to that component of weight:

where,
W = Weight of Wagon = 150 N
θ = Angle of Inclinition = 20°
Therefore,

<u>F = 51.3°</u>