1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
balandron [24]
3 years ago
5

An object with a charge of -3.2 uC and a mass of 1.0×10^(-2) kg experiences an upward electric force, due to a uniform electric

field, equal in magnitude to its weight.
If the electric charge on the object is doubled while its mass remains the same, find the direction and magnitude of its acceleration.

upward
downward
to the left
to the right

Physics
1 answer:
USPshnik [31]3 years ago
6 0

Answer:

The magnitude of the acceleration is equal to 19.6m/s² and the acceleration is directed upwards though the magnitude of the charge has doubled. This is because the electric force is directed upwards and from newton's second law of motion the charge will have acceleration in the same direction as the electric force on the charge.

Explanation:

The detailed solution can be found in the attachment below.

Thank you for reading and I hope this is helpful to you.

You might be interested in
What fraction of chlorine-36 remains UN-decayed after 800,000 years?
Natasha2012 [34]
Three quarters remain un-decayed
6 0
2 years ago
The power rating of a light bulb (such as a 100-W bulb) is the power it dissipates when connected across a 120-V potential diffe
bazaltina [42]

To solve this problem we will apply the concepts related to the calculation of power, from the two electrical forms:

P = VI

P = \frac{V^2}{R}

Here,

V = Voltage

I = Current

R= Resistance

P = Power

PART A)

R = \frac{V^2}{P}

Replacing,

R = \frac{(120V)^2}{150W}

R = 96\Omega

Resistance of bulb is 96\Omega

PART B)

I = \frac{P}{V}

I = \frac{150W}{120V}

I = 1.25A

The bulb will draw 1.25A current

7 0
3 years ago
An elevator motor in a high-rise building can do 3500 kJ of work in 5 min. Find the power developed by the motor. Explain if you
Ilya [14]

Answer:

P = 11666.6 W

Explanation:

Given that,

Work done by the motor, W = 3500 kJ

Time, t = 5 min = 300 s

We need to find the power developed by the motor. Power developed is given by :

P=\dfrac{E}{t}\\\\P=\dfrac{3500\times 10^3}{300}\\\\P=11666.7\ W

So, the required power is 11666.6 W.

4 0
3 years ago
Why do scientists believe that light is made of waves?
skelet666 [1.2K]

Answer:

Scientists believe that light is made of waves because experiments have shown that, based on Huygens's principle, waves have the ability to bend and change direction.

Explanation:

4 0
3 years ago
Shania says that the fulcrum is part of the lever and Ali says that the pivot is part of a lever. who is correct? ​
suter [353]

Answer:

Shania is correct because a fulcrum is the lower part of a lever and a pivot is  not part.

Explanation:

5 0
3 years ago
Read 2 more answers
Other questions:
  • What would change in the sound wave if you adjusted the volume of your voice? A) amplitude B) frequency C) pitch D) wavelength
    6·1 answer
  • The dimensions of a room are 16.40 m long, 4.5 m wide and 3.26 m high. What is the volume of the room in cubic meters? Express y
    9·1 answer
  • Select the object that has the most gravitational force.
    11·2 answers
  • What is the name for the compound SO3?
    12·2 answers
  • The diagram shows monochromatic light passing through two openings.
    15·1 answer
  • A bullet from a policeman's handgun travels at 200 meters per second and has a mass of 0.02 kg.
    9·1 answer
  • In the form of radioactive decay known as alpha decay, an unstable nucleus emits a helium-atom nucleus, which is called an alpha
    6·1 answer
  • How many significant figures are there in 0.0000303?
    11·1 answer
  • A payload of mass m, where m
    8·1 answer
  • A roller coaster's velocity at the bottom of a hill is 35.0 m/s, 5.00 seconds later it reaches the top of the hill with a veloci
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!