An object with a charge of -3.2 uC and a mass of 1.0×10^(-2) kg experiences an upward electric force, due to a uniform electric
field, equal in magnitude to its weight.
If the electric charge on the object is doubled while its mass remains the same, find the direction and magnitude of its acceleration.
upward
downward
to the left
to the right
If the electric charge on the object is doubled while its mass remains the same, find the direction and magnitude of its acceleration.
upward
downward
to the left
to the right
1 answer:
Answer:
The magnitude of the acceleration is equal to 19.6m/s² and the acceleration is directed upwards though the magnitude of the charge has doubled. This is because the electric force is directed upwards and from newton's second law of motion the charge will have acceleration in the same direction as the electric force on the charge.
Explanation:
The detailed solution can be found in the attachment below.
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Answer:
a) The work required to stretch the spring from 20 centimeters to 25 centimeters is 0.313 joules, b) The area of the region enclosed by one loop of the curve is
.
Explanation:
a) The work, measured in joules, is a physical variable represented by the following integral:
Where
,
- Initial and final position, respectively, measured in meters.
- Force as a function of position, measured in newtons.
Given that and the fact that
when
, the spring constant (
), measured in newtons per meter, is:
Now, the work function is obtained:
The work required to stretch the spring from 20 centimeters to 25 centimeters is 0.313 joules.
b) Let be . The area of the region enclosed by one loop of the curve is given by the following integral:
By using trigonometrical identities, the integral is further simplified:
The area of the region enclosed by one loop of the curve is
.