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Margarita [4]
4 years ago
6

The persistence of vision for normal eye is

Physics
2 answers:
attashe74 [19]4 years ago
6 0

Answer:

The answer is 1/16

Explanation:

1. Persistence of vision refers to the optical illusion that occurs when visual perception of an object does not cease for some time after the rays of light proceeding from it have ceased to enter the eye. 2. The persistence of vision for normal eye is 1/16 if a second.

pashok25 [27]4 years ago
4 0

Answer:

idk

Explanation:

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Can u answer 4 and 5 for me
Luda [366]
I don’t know what the answers are
8 0
4 years ago
The speed for a car that went a distance of 125 miles in 2 hours time is ______. Question 2 options: 250 meters/sec 62.5 miles/h
Goryan [66]

Answer:

62.5 miles per hour

Explanation:

Speed = Distance travelled / Time taken

Speed = 125/2 = 62.5

You derive the units of the speed...by using the speed formula....,

Speed = Distance/Time

Speed = miles/hour

Hence the units for the speed = miles/hour

5 0
3 years ago
A muscle inserts 1.5 cm from the joint axis and exerts 300 N of force at an angle of pull of 60 degrees. How much torque is prod
Amanda [17]

Answer:

torque = 3.897 N-m

Explanation:

given data

force = 300 N

angle = 60 degree

distance = 15 cm

to find out

torque

solution

we will apply here torque formula that is given below

torque = force × sinθ × distance    ...................1

put here all these value in equation 1

we get torque

torque  = force × sinθ × distance

torque  = 300 × sin60 × 1.5 ×10^{-2}

torque  = 300 × 0.8660 × 1.5 ×10^{-2}

torque  = 259.80 × 1.5 ×10^{-2}

torque  = 389.711 ×10^{-2}

torque = 3.897 N-m

8 0
3 years ago
a car accelerates uniformly from rest to a speed of 65 km/h (18 m/s) in 12s. Find the distance the car travels during this time?
Vinil7 [7]

The car's speed was zero at the beginning of the 12 seconds,
and 18 m/s at the end of it.  Since the acceleration was 'uniform'
during that time, the car's average speed was (1/2)(0 + 18) = 9 m/s.

12 seconds at an average speed of 9 m/s  ==>  (12 x 9) = 108 meters .

==========================================

That's the way I like to brain it out.  If you prefer to use the formula,
the first problem you run into is:  You need to remember the formula !

The formula is        D = 1/2 a T²

                   Distance = (1/2 acceleration) x (time in seconds)²

             Acceleration = (change in speed) / (time for the change)
                                  =        (18 m/s)            /        (12 sec)
                                  =                      1.5 m/s² .

                  Distance  =  (1/2 x 1.5 m/s²) x (12 sec)²
                                  =       (0.75 m/s²)  x  (144 sec²)  =  108 meters .

5 0
4 years ago
A 2.0kg pendulum swings from point A of a height of 0.10m to a point B of the same height. The heights are relative to the lower
mr_godi [17]
Please press “Thanks!” after viewing my answer:
The change in Gravitational Potential Energy (GPE) is actually 0! Think about it:
What is the formula for it?
Well, GPE = mgh.
So, when the height is the same in both cases, we know the gravitational potential energy is the same. Therefore, change in GPE = 0.
Sure, GPE did transform to KE during the swing, but all of that KE transformed back into the original amount of GPE.

Hope this helped! Please press “Thanks!”
4 0
3 years ago
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