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Cerrena [4.2K]
3 years ago
10

Consider a golf club hitting a golf ball. To a good approximation, we can model this as a collision between the rapidly moving h

ead of the golf club and the stationary golf ball, ignoring the shaft of the club and the golfer. A golf ball has a mass of 46 g. Suppose a 200 g club head is moving at a speed of 40 m/s just before striking the golf ball. After the collision, the golf ball's speed is 60 m/sa) what is the momentum of the club and ball system right before the collision?b) immediately after the collision, the momentum of the club and ball system will be? (less than, the same as, or greater than before the collision)c)a manufacturer makes a golf ball that compresses more than a traditional golf ball when struck by a club. how will this affect the average force during the collison?d) by approximately how much does the club head slow down as a result of hitting the ball?Please show all work!
Physics
1 answer:
vekshin13 years ago
6 0

Answer:

1. 8.0kg * m/s

2. The same as before the collision

3. The force will decrease

4. 14 m/s

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Suppose a 1300 kg car is traveling around a circular curve in a road at a constant
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F = 4212 N

Explanation:

Given that,

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Radius of curve, r = 25 m

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2 years ago
A box with mass (m) it's sliding along on a friction-free surface at 9.87 m/s at a height of 1.81 meters. It travels down the hi
Rus_ich [418]
A) The answer is 11.53 m/s

The final kinetic energy (KEf) is the sum of initial kinetic energy (KEi) and initial potential energy (PEi).
KEf = KEi + PEi

Kinetic energy depends on mass (m) and velocity (v)
KEf = 1/2 m * vf²
KEi = 1/2 m * vi²

Potential energy depends on mass (m), acceleration (a), and height (h):
PEi = m * a * h

So:
KEf = KEi + <span>PEi
</span>1/2 m * vf² =  1/2 m * vi² + m * a * h
..
Divide all sides by m:
1/2 vf² =  1/2 vi² + a * h

We know:
vi = 9.87 m/s
a = 9.8 m/s²
h = 1.81 m

1/2 vf² =  1/2 * 9.87² + 9.8 * 1.81
1/2 vf² = 48.71 + 17.74
1/2 vf² = 66.45
vf² = 66.45 * 2
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vf = √132.9
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b) The answer is 6.78 m

The kinetic energy at the bottom (KE) is equal to the potential energy at the highest point (PE)
KE = PE

Kinetic energy depends on mass (m) and velocity (v)
KE = 1/2 m * v²

Potential energy depends on mass (m), acceleration (a), and height (h):
PE = m * a * h

KE = PE
1/2 m * v² = m * a * h

Divide both sides by m:
1/2 * v² = a * h
v = 11.53 m/s
a = 9.8 m/s² 
h = ?

1/2 * 11.53² = 9.8 * h
1/2 * 132.94 = 9.8 * h
66.47 = 9.8 * h
h = 66.47 / 9.8
h = 6.78 m
3 0
3 years ago
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