Atomic number The atomic number of each element is different than other Elements.
The answer is more protons than electrons.
Answer:
The Flow rate = 0.0208 mL/min
Explanation:
Data provided:
Rate of dose = 39 mg every 30 min = (39/30) mg/min = 1.3 mg/min
also,
125mg of methylprednisolone is present in every 2 mL
thus,
concentration = (125/2) mg/mL = 62.5 mg/mL
Now,
The flow rate is given as:
Flow rate = Rate / Concentration
on substituting the respective values, we get
Flow rate = (1.3 mg/min) / (62.5mg/mL)
or
The Flow rate = 0.0208 mL/min
Empirical formula of ionic compound is FeO. In which the composition of atoms is 1 : 1.
Empirical formula of an ionic compound is defined as the formula which gives whole number ratio of atoms of various elements present in molecule of compund.
mass of iron in compound = 34.95 g
molar mass of iron = 55.8 g
mass of oxygen in compound = 15.05 g
molar mass of oxygen = 32 g
number of moles of iron present in the compound are ratio of mass of iron in compound/ molar mass of iron
number of moles of iron in compound= 34.95 / 55.8 = 0.6263 ~ 1
number of moles oxygen in compound= 15.05/ 32 = 0.473 ~ 0.5
the ratio of the number of oxygen atoms to number of iron atoms present in one formula unit of iron compund is 2×0.5 / 1 = 1 : 1
Hence , the required empirical formula of iron compound is FeO.
To learn more about Emiprical formula, refer:
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<u>Answer:</u> The net ionic equation for the given reaction is 
<u>Explanation:</u>
Net ionic equation of any reaction does not include any spectator ions.
Spectator ions are the ions which do not get involved in a chemical equation. It is also defined as the ions that are found on both the sides of the chemical reaction when it is present in ionic form.
The chemical equation for the reaction of hydrochloric acid and potassium sulfite is given as:
Ionic form of the above equation follows:
As, potassium and chloride ions are present on both the sides of the reaction, thus, it will not be present in the net ionic equation.
The net ionic equation for the above reaction follows:
Hence, the net ionic equation for the given reaction is written above.
