2 years ago

What is the volume of an object that has Mass=100g and Density= 745g/mL.

Physics

1 answer:

lana66690 [7]2 years ago

6 0

Answer:0.13ml

Explanation:

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An object, initially at rest, is subject to an acceleration of 34 m/s^2. How long will it take for that object to reach 3400m ?

Norma-Jean [14]

Vf^2 = Vi^2 + 2ad
a= 34 m/s^2
Vi = 0 m/s
d = 3400m

Vf = 480.83 m/s

a=v/t
t=v/a
t=480.83/34
t=14.142 s

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2 years ago

Your cat "Ms." (mass 7.00 {\rm kg}) is trying to make it to the top of a frictionless ramp 2.00 {\rm m} long and inclined upward

lbvjy [14]

Answer:

Final velocity at the top of the ramp is 6.58m/s

Explanation

Check the attachment

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2 years ago

A force of 45 N is applied tangentially to the rim of a solid disk of radius 0.12 m. The disk rotates about an axis through its

bearhunter [10]

Answer:

Mass of the disk will be 2.976 kg

Explanation:

We have given force F = 45 N

Radius of the disk r = 0.12 m

Angular acceleration $\alpha =140rad/sec^2$

We know that torque $\tau =I\alpha$

And $\tau =Fr$

So $Fr=I\alpha$ , here I is moment of inertia

So $50\times 0.12=I\times 140$

$I=0.0428kgm^2$

We know that moment of inertia $I=\frac{1}{2}mr^2$

So $0.0428=\frac{1}{2}\times m\times 0.12^2$

m = 2.976 kg

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2 years ago

An electric generator converts kinetic energy into --------<br> energy.

pickupchik [31]

The correct answer to the question is : Electric energy

EXPLANATION :

As per the question, we have an electric generator.

Before coming into any conclusion, first we have to understand the function of generator.

The generator is attached to the turbine. When the turbine rotates, the generator also starts rotating with it. Thanks to electromagnetic induction, the electricity is produced in the coil attached to the generator when it rotates.

Hence, from above, it is obvious that kinetic energy is converted into electric energy.

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2 years ago

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You have been hired by a "storm chaser" as an assistant. This individual loves to find locations at which tornadoes and violent

Studentka2010 [4]

Answer:

58.44 C

Explanation:

Electric field is found by

$E=\frac {\sigma}{\epsilon_o}=\frac {Q}{A\epsilon_o}$

Therefore, the charge is

$Q=EA\epsilon_o
$

$Q= 4.00 ✕ 10^{6} N/C*1.65 *10^{6} m^{2}*8.854*10^{-12}= 58.4364 C
$

Therefore, required charge is 58.44 C

5 0

2 years ago