What is the area and width

Is not a polygon because ???

Julli [10]

Answer:

The shape includes a curve; all polygons are supposed to have straight sides, which this shape does not.

7 0

2 years ago

Read 2 more answers

Write a number that has four digits with the same number in all places,such as 4,444. Circle the digits with the greatest value.

Citrus2011 [14]

9999

first 3 nines have the greater value but the first one has the highest and the least one is the last nine.

6 0

3 years ago

Mario claims that if the dinominator of a fraction is a prime number, then its decimal form is a repeting decimal. Do you agree?

vodomira [7]

Answer:

I do not agree because Mario's claim is not general.

Step-by-step explanation:

Prime numbers: These are a set of numbers that are divisible by 1 and itself only. Examples are: 2, 3, 5, 7. 11 etc.

And a denominator is the divisor in a given fraction.

Considering the following fractions whose denominators are prime numbers:

$\frac{2}{3}$ = 0.66666666...

$\frac{1}{7}$ = 0.142857142

$\frac{5}{11}$ = 0.45454545...

$\frac{3}{13}$ = 0.23076923

$\frac{1}{7}$ = 0.142857142

It could be observed that Mario's claim is not a general principle which is applicable to all fractions with a prime denominator. Thus, I do not agree with his claim.

4 0

3 years ago

Please answer 5,6,7. With explanation.

Anestetic [448]

First you need to know some rules 2 numbers that are the same with coefficients divided : you differentiate those coeff
and multyplied :you sum up them

12x^8/3x^3= 4x^8-3=4x^5

20^2x=20^x*20^x

m^5*m^-7=m^5-7=m^-2

8 0

3 years ago

According to a study done by Wakefield Research, the proportion of Americans who can order a meal in a foreign language is 0.47.

UNO [17]

Answer:

Probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is 0.19766.

Step-by-step explanation:

We are given that according to a study done by Wake field Research, the proportion of Americans who can order a meal in a foreign language is 0.47.

Suppose a random sample of 200 Americans is asked to disclose whether they can order a meal in a foreign language.

Let $\hat p$ = sample proportion of Americans who can order a meal in a foreign language

The z-score probability distribution for sample proportion is given by;

Z = $\frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion

p = population proportion of Americans who can order a meal in a foreign language = 0.47

n = sample of Americans = 200

Probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is given by = P( $\hat p$ > 0.50)

P( $\hat p$ > 0.06) = P( $\frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ > $\frac{0.5-0.47}{\sqrt{\frac{0.5(1-0.5)}{200} } }$ ) = P(Z > 0.85) = 1 - P(Z $\leq$ 0.85)

= 1 - 0.80234 = 0.19766

Now, in the z table the P(Z $\leq$ x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 0.85 in the z table which has an area of 0.80234.

Therefore, probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is 0.19766.

4 0

3 years ago