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PilotLPTM [1.2K]
3 years ago
9

What is the area and width

Mathematics
1 answer:
Airida [17]3 years ago
8 0
Area is 169 square feet

Width is 13 feet
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I need help please
nlexa [21]

Answer:

49

Step-by-step explanation:

No she is not correct because we dont have only one angle angle G is 90.

So we can easily find the angle D

180-(90+41) =49

7 0
2 years ago
Help plz it's homework and I need it fast thank you
Zarrin [17]
You can write it as 721 over 1000, then simplify from there
8 0
3 years ago
In the diagram below, O is circumscribed about quadrilateral DEFG. What is the value of x?
Fofino [41]

Answer:

A. 70

Step-by-step explanation:

The given quadrilateral DEFG is a cyclic quadrilateral.

\angle F+70\degree=180\degree...opposite angles of a cyclic quadrilateral are supplementary.

\implies \angle F=180\degree-70\degree

\implies \angle F=110\degree

The sum of angles in a quadrilateral is 360 degrees.

x-10+70+110+120=360

x+290=360

x=360-290

x=70\degree

7 0
3 years ago
Which line plot displays a data set with an outlier?
Westkost [7]

Answer: See attached, the top right

Step-by-step explanation:

      <u>What is an outlier?</u> An outlier, in a data set, is a data value that is outside the overall pattern of distribution.

   This means the answer to your question is the top right because the data value of 13 is outside the overall pattern, hence an outlier.

8 0
2 years ago
Read 2 more answers
Find the distance between A and B.
Papessa [141]

Answer:

The result is d = 2\sqrt{5} units.

Step-by-step explanation:

The coordinates for A and B:

A = (-2, 0)

B = (2, 2)

-To find the distance between A and B, you need the distance formula:

d = \sqrt{(x_{2} - x_{1})^2 + (y_{2}-y_{1})^2} Where the first coordinate is (x_{1},y_{1}) and  the second coordinate is (x_{2}, y_{2}).

-Use the coordinates A and B for the equation:

d = \sqrt{(2+2)^2 + (2-0)^2}

-Then, you solve the equation:

d = \sqrt{(2+2)^2 + (2-0)^2}

d = \sqrt{(4)^2 + (2)^2}

d = \sqrt{16 + 4}

d = \sqrt{20}

d = 2\sqrt{5}

So, therefore the distance is 2\sqrt{5} units.

7 0
3 years ago
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