Answer:
B) 40 km West
Explanation:
Let position of B is origin so with respect of City B the position of A is given as
south of city B
now Bus starts from City A and travels a distance of 50 km at 37 degree North of East to reach city C
so it is
now the position of C is given with respect to A
in order to find the position of C with respect to B we can say
so in order to reach at city B from city C bus has to travel 40 km towards West
Answer:
The magnitude of the acceleration of the 19 kg block is 1.414 m/s²
Explanation:
From Newton's second law of motion;
where;
m is the mass of the objects involved, kg
a is the acceleration of the object, m/s²
different forces on the block and string
⇒force due to 15 kg block
=mgcosθ = 15×9.8×cos20 = 15×9.8×0.9396
= 138.12 N
⇒Tensional Force on 19 kg mass:
T = mg = 19×9.8 = 186.2 N
186.2 - 138.12 = a(15+19)
48.08 = a(34)
a = 48.08/34
a = 1.414 m/s²
Therefore, the magnitude of the acceleration of the 19 kg block is 1.414 m/s²