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blsea [12.9K]
3 years ago
15

What is the volume of 0.23kg of pure water

Chemistry
2 answers:
tatyana61 [14]3 years ago
8 0

<u>Answer:</u> The volume of pure water is 230cm^3

<u>Explanation:</u>

To calculate density of a substance, we use the equation:

Density=\frac{Mass}{Volume}

We are given:

Density of pure water = 1g/cm^3

Mass of pure water = 0.23kg = 230 g     (Conversion factor: 1 kg = 1000 g)

Putting values in above equation, we get:

1g/cm^3=\frac{230g}{\text{Volume of pure water}}\\\\\text{Volume of pure water}=230cm^3

Hence, the volume of pure water is 230cm^3

vichka [17]3 years ago
7 0
M = 0,23kg = 230g
d = 1g/cm³

V = 230g / 1g/cm³ = 230cm³ = 0,23L
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An aqueous solution of sodium thiosulfate releases heat when it crystallizes. What would happen when sodium thiosulfate crystals
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"What is the change of entropy for 3.0 kg of water when the 3.0 kg of water is changed to ice at 0"
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-3670.33 J/K

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Mathematically,  change of Entropy can be expressed as,

ΔS = ΔH/T ....................................... Equation 1

Where ΔS = Change of entropy, ΔH = heat change, T = temperature.

ΔH = -(Lf×m).................................... Equation 2

Note: ΔH is negative because heat is lost.

Where Lf = latent heat of ice = 3.34×10⁵ J/kg, m = 3.0 kg, m = mass of water = 3.0 kg

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what is the concentration of hydroxide ions after 50.0 ml of 0.250 m naoh is added to 120 ml of 0.200 m na2so4? please show all
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The concentration of the hydroxide ions after 50 ml of 0.250M NaOH is added to 120ml of 0.200M Na2SO4 is 7.35 x 10^-2 M.

What is meant by concentration?

Concentration is the total amount of solute present in the given volume of solution. this is expressed in terms of molarity, molality, mole fraction, normality etc. The term concentration mostly refers to the solvents and solutes present in the solution.

Concentration of hydroxide ions can be calculated by,

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where M (OH^-) = concentration of hydroxide ions, V(NaOH) = volume of NaOH, M(NaOH) = concentration of NaOH.

Therefore, the concentration of the hydroxide ions after 50 ml of 0.250M NaOH is added to 120ml of 0.200M Na2SO4 is 7.35 x 10^-2 M.

To learn more about concentration click on the given link brainly.com/question/17206790

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