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kobusy [5.1K]
3 years ago
9

Which of the following questions is most testable through scientific experimentation?

Chemistry
2 answers:
Dominik [7]3 years ago
3 0
The Question that I believe that is the most testable through scientific experimentation would be the first question.

Which gelatin takes longer to set. Gelatin with fruit or gelatin without fruit.
Genrish500 [490]3 years ago
3 0

Answer:

Which gelatin takes longer to set: gelatin with fruit or gelatin without fruit?

Explanation:

Option A is Correct. In chemistry the rate of reaction or kinetics is always studied so this is most testable through scientific experimentation

Option B is Incorrect. This is more relevant in the hospitality business and is not testable through scientific experimentation.  

Option C is Incorrect. This is more relevant in the hospitality business.  

Option D is Incorrect. This has more to do with commerce or economics.  

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Gabriel and his friend found a piece of metal which they want to
Dominik [7]
50/5.2 that’s the equation that you have to solve then whatever comes out yo calculator is the answer
6 0
3 years ago
Read 2 more answers
The Nutrition Facts label for crackers states that one serving contains 19 g of carbohydrate, 4 g of fat, and 2 g of protein. Wh
sp2606 [1]

<u>Answer:</u> The amount of kilocalories contained in the given serving of crackes is 0.120 kCal

<u>Explanation:</u>

<u>As per the USDA:</u>

Carbohydrates provide 4 calories per gram, protein provides 4 calories per gram, and fat provides 9 calories per gram

We are given:

Mass of fat in the crackers = 4 g

Mass of carbohydrates in the crackers = 19 g

Mass of protein in the crackers = 2 g

Conversion factor used:  1 kCal = 1000 Cal

Applying unitary method:

  • <u>For Fat:</u>

1 gram of fat provides 9 calories

So, 4 gram of fat will provide = \frac{9}{1}\times 4=36Cal=0.036kCal

  • <u>For Carbohydrates:</u>

1 gram of carbohydrates provides 4 calories

So, 19 gram of carbohydrates will provide = \frac{4}{1}\times 19=76Cal=0.076kCal

  • <u>For Proteins:</u>

1 gram of proteins provides 4 calories

So, 2 gram of fat will provide = \frac{4}{1}\times 2=8Cal=0.008kCal

Total kilocalories per serving = [0.036 + 0.076 + 0.008] kCal = 0.120 kCal

Hence, the amount of kilocalories contained in the given serving of crackes is 0.120 kCal

8 0
3 years ago
Pls someone help me out
SpyIntel [72]
Do you still need help
4 0
2 years ago
A sealed reaction vessel initially contains 1.113×10-2 moles of water vapor and 1.490×10-2 moles of CO(g).
Molodets [167]

Answer:

Kc =\frac{[8.326x10-3]^{1} }{[1.113x10-2]^{1}[1.490x10-2]^{1}  }

Kc = 50.2059

Explanation:

1. Balance the equation

2. Use the Kc formula

Remember that pure substances, like H2 are not included on the Kc formula

4 0
3 years ago
What is the molality of a solution if 100.0 g of glucose (C&amp;Hi20e) were dissolved into 750. mL of water?
hodyreva [135]

<u>Answer:</u> The molality of solution is 0.740 m.

<u>Explanation:</u>

To calculate the mass of solvent (water), we use the equation:

Density=\frac{Mass}{Volume}

Volume of water = 750 mL

Density of water = 1 g/mL

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{750mL}\\\\\text{Mass of water}=750g

To calculate the molality of solution, we use the equation:

Molarity=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

Where,

m_{solute} = Given mass of solute (C_6H_{12}O_6) = 100.0 g

M_{solute} = Molar mass of solute (C_6H_{12}O_6) = 180 g/mol

W_{solvent} = Mass of solvent (water) = 750 g

Putting values in above equation, we get:

\text{Molality of }C_6H_{12}O_6=\frac{100\times 1000}{180\times 750}\\\\\text{Molality of }C_6H_{12}O_6=0.740m

Hence, the molality of solution is 0.740 m.

6 0
3 years ago
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