Answer:
1.0M HCl is the concentration of the acid
Explanation:
Based on the reaction, 1 mole of NaOH reacts per mole of HCl. That means the moles added of NaOH in the neutralization = Moles of HCl in the solution. With the moles and the volume in Liters we can find the molar concentration of HCl
<em>Moles NaOH = Moles HCl:</em>
25.0mL = 0.025L * (2.0moles / L) = 0.050moles HCl
<em>Molarity:</em>
0.050moles HCl / 0.0500L =
<h3>1.0M HCl is the concentration of the acid</h3>
Answer:
Rb<K<Ga<As<Se<S
Explanation:
We must remember that first ionization energy decreases down the group and increases across the period.
First ionization energy decreases down the group because of the addition of more shells which increases the distance between the nucleus and the outermost electron. Hence, Rb has a lower ionization energy that K.
Across the period, increase in the size of the nuclear charge causes the pull of the nucleus on the outermost electrons to increase thereby increasing the ionization energy. Hence ionization energy increases across the period. For this reason, the ionization energy of Ga<As<Se as shown.
Answer:
koh
Explanation:
kOh has a ph level of 10.89
The balanced reaction
is:
AgNO3 + NaCl = NaNO3 + AgCl
<span>We are given the amount of silver nitrate to react with sodium chloride. This
will be our starting point.</span>
15.0 mol AgNO3 (1 mol AgCl / 1
mol AgNO3 ) =15.0 mol AgCl
The amount of moles produced is the same with the amount of the given reactant since they only one is to one ratio.
