Answer:
6CO2+6H2O->C6H12O6+6O2
Explanation:
CO2+H2O+C6H12O6+O2 This wrong when you write a formula. Don't savage the given question. caused it will affect the same answer.
It will write as this CO2+H20->C6H12O6+O2
So, Think what will you use the numbers in a side of chemical formula/name I am using the "eyes to eyes "caused you need to it properly. If you are not good at it use other method calculate each chemical name example. we have C=1,O=2 then, H=2,O=1 and they other side goes to the arrow is C=6 H=12O=6 ,O=2 I will think what number will make it balance for them and what is lucking see in the my answers what I add in the equation think carefully I didn't change or erase a number of them. Caused it is wrong if you do that. Thank you
The number of atoms present in carbon, specifically Carbon-12, is the number of atoms present in 1 gram of the substance. One moles of the substance weighs approximately 12.01 g/mole. The unit suggests that every mole of carbon weighs 12.01 grams.
Answer:
True/Yes
Explanation:
Hydrogen peroxide and vinegar: A component of vinegar is acetic acid, and according to Lu, this acetic acid will form a chemical called peracetic acid when mixed with hydrogen peroxide. Peracetic acid is toxic and corrosive, meaning it can damage or break down the surface it's applied to.
Answer:
please mark brainlest and it's Procedure 1: One of the products was a gas that escaped into the air.
Procedure 2: A gas from the air reacted with one of the other reactants
Explanation:
the gas ca evaporate so it would'nt be a or c and b dosent make sense.
Answer:
C. the relative number of atoms of each element, using the lowest whole ratio.
Explanation:
The empirical formula is how we simplify the whole formula to simplify it to its smallest indivisible parts.
It is definitely not the actual number of atoms. If you see an empirical formula, don't think that it's the full thing.
It is also not a representation of a compound to show its atoms' arrangement: this would be a Lewis dot structure, or a ball and stick model, or something similar. We don't use the empirical formula for this purpose.
