Answer:
34g
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
H2S + 2AgNO3 —> 2HNO3 + Ag2S
Next, we shall determine the number of mole of H2S required to react with 2 moles of AgNO3.
This is illustrated below:
From the balanced equation above,
We can see that 1 mole of H2S is required to react completely with 2 moles of AgNO3.
Finally, we shall convert 1 mole of H2S to grams. This is shown below:
Number of mole H2S = 1 mole
Molar mass of H2S = (2x1) + 32 = 34g/mol
Mass = number of mole x molar Mass
Mass of H2S = 1 x 34
Mass of H2S = 34g
Therefore, 34g of H2S is needed to react with 2 moles of AgNO3.
I believe it is C, but I can't guarantee it.
Answer:
The answer is
<h2>5.50</h2>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula
From the question
mass = 22 g
density = 4 g/mL
The volume is
We have the final answer as
<h3>5.50 mL</h3>
Hope this helps you
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