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ziro4ka [17]
3 years ago
13

35 Before the discovery of oxygen some scientists had a different theory about burning.

Chemistry
2 answers:
almond37 [142]3 years ago
7 0
C phlogiston hope this helps
skad [1K]3 years ago
3 0

Answer:

<h2>B i have to search it like 23 hours to find it but Thank you for sharing your question :)</h2>
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A sample of helium gas inside a closed but flexible container occupies a volume of 355mL at 23°C. If the pressure is held consta
guapka [62]

Answer:

978.19° C

Explanation:

P1V1/T1 =P2V2/T2     Since the pressure is constant, this can be written as

V1/T1 = V2/T2      RE-ARRANGE TO

V2 *  T1/V1   = T2       Note:  T must be in Kelvin!!

1.5 L  *  (273.15 + 23)  / (.355 L ) = T2 = 1251.338 K  =978.19 C

6 0
2 years ago
Helppppp will mark brainlest
ss7ja [257]

Answer:

if you will decrease the HCO3- so the less H+ ion will be form and reaction will more likely shift to product and when HCO3- decreases pH value increases and vica versa for the increasing HCO3 the more H+ ion will be form and reaction will shift to product and the pH value will decreases!!

I've doubt in reaction shift coz whatever is the amount of HCO3- this is completely gonna form number of H+ so reaction shift may or may not be same!!

5 0
3 years ago
What is the pressure exerted by 68.0 g of nitrogen trihydride gas in a 50.0L container at 30.0 C?
Cloud [144]

Answer:

Molecular mass of NH3 = ( 14 + 3 ) = 17 g

PV =  \frac{m}{m _{r}} RT \\ P \times 50.0 \times  {10}^{ - 6}  =  \frac{68.0}{17}  \times 8.314 \times (30.0 + 273) \\ P =  \frac{68.0 \times 8.314 \times 303}{17 \times 50.0 \times  {10}^{ - 6} }  \\ P = 2.02 \times  {10}^{8}  \: Pascals

8 0
3 years ago
___ is the sacrifice involved in making one decision over another
Scilla [17]
Opportunity cost

Opportunity cost is the benefit, profit or value that could have been received or obtained but instead given up in favor of another alternative or course of action. Every situation has several alternatives and every resource has several alternative uses as well. Thus, every decision comes with it an opportunity cost. <span>
</span>
4 0
4 years ago
When 28.0 g of acetylene reacts with hydrogen, 24.5 g of ethane is produced. What is the percent yield of C2H6 for the reaction?
Afina-wow [57]

Answer:

Y=75.6\%

Explanation:

Hello.

In this case, since no information about the reacting hydrogen is given, we can assume that it completely react with the 28.0 g of acetylene to yield ethane. In such a way, via the 1:1 mole ratio between acetylene (molar mass = 26 g/mol) and ethane (molar mass = 30 g/mol), we compute the yielded grams, or the theoretical yield of ethane as shown below:

m_{C_2H_6}^{theoretical}=28.0gC_2H_2*\frac{1molC_2H_2}{26gC_2H_2}*\frac{1molC_2H_6}{1molC_2H_2}  *\frac{30gC_2H_6}{1molC_2H_6}\\ \\m_{C_2H_6}^{theoretical}=32.3gC_2H_6

Hence, by knowing that the percent yield is computed via the actual yield (24.5 g) over the theoretical yield, we obtain:

Y=\frac{24.5g}{32.3g}*100\%\\ \\Y=75.6\%

Best regards.

3 0
3 years ago
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