How much heat in kilojoules is required to melt an ice cube with a mass of 18.6 g at 0 °C? The Lf for water is 333 J/g.

1 answer:

3 0

Q = m.Lf.
Here, m = 18.6 g
Lf = 333 J/g

Substitute their values,
Q = 18.6 × 333 = 6193.8 J

We know, 1 KJ = 1000 J
So, 6193.8 J = 6.193 KJ

In short, Your Answer would be Option D

Hope this helps!

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